Cody

Roger Stafford

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 Roger Stafford received Quiz Master badge for Solution 1664697 on 2 Nov 2018 on 27 Feb 2012 Roger Stafford submitted a Comment to Solution 51711 Yes, you are right S L, a direct brute force summation is surely not the most efficient method of determining the sums of these series. You are the only one so far with a valid solution that met the 50*eps tests. In fact your answers are very much closer than that to mine, within a few eps. However, there is another single analytic function that can be used which is much simpler and would undoubtedly give you a lower "size" than 92 if you or others can find it. R. Stafford on 26 Feb 2012 on 26 Feb 2012 on 25 Feb 2012 on 25 Feb 2012 Roger Stafford submitted a Comment to Solution 50615 I am pleased that you solved this problem, David. Congratulations! I didn't find any particularly easier way of solving it. The crucial step is showing that the probability density is proportional to your 1/y^3 for points within the corresponding "kite-shaped region". I used the Jacobian between two coordinate systems to show that. After dividing that region into two halves everything falls into place, though in my dotage I had to make heavy use of the Symbolic Toolbox to check for errors. (I hope this problem will serve as a warning to people who recommend this method of producing random numbers with a predetermined sum.) R. Stafford on 24 Feb 2012 Roger Stafford submitted a Comment to Solution 47851 It is inherent in the definition of P here that the density, dP/dA, must increase as P increases and therefore dA/dP must decrease. In your proposed solution you have dA/dP increasing as P increases. R. Stafford on 23 Feb 2012 Roger Stafford received Commenter badge for Solution 47851 on 23 Feb 2012 on 17 Feb 2012 on 9 Feb 2012 on 8 Feb 2012 on 7 Feb 2012 on 7 Feb 2012 on 6 Feb 2012 on 6 Feb 2012 on 6 Feb 2012 on 6 Feb 2012 on 5 Feb 2012 on 5 Feb 2012 on 2 Feb 2012 Roger Stafford received Creator badge for Problem 225. Subdivide the Segment on 2 Feb 2012 on 2 Feb 2012 on 30 Jan 2012 on 30 Jan 2012 on 29 Jan 2012 on 29 Jan 2012 on 29 Jan 2012 on 28 Jan 2012 on 28 Jan 2012 on 28 Jan 2012 on 28 Jan 2012 on 28 Jan 2012 on 28 Jan 2012 on 28 Jan 2012 on 28 Jan 2012 on 28 Jan 2012 on 27 Jan 2012 on 27 Jan 2012 on 27 Jan 2012 on 27 Jan 2012 on 27 Jan 2012 on 27 Jan 2012 on 27 Jan 2012 on 27 Jan 2012 on 27 Jan 2012 on 26 Jan 2012 on 26 Jan 2012
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