Problem 74. Balanced number

Created by Cody Team

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Solve

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5893 Solutions
2514 Solvers

Last Solution submitted on Jan 19, 2023

Last 200 Solutions

Problem Comments

1 Comment

1 Comment

GEORGIOS BEKAS on 25 Jan 2018

there is a problem with the test.
it does not accept the following code:
s1=[]
s2=[]
l=length(s)
if mod(l,2)~= 0
for i = 1:ceil(length(s)/2)-1
s1 = [s1,str2double(s(i))]
end
for i = ceil(length(s)/2)+1:l
s2=[s2,str2double(s(i))]
end
else
for i = 1:ceil(length(s)/2)
s1 = [s1,str2double(s(i))]
end
for i = ceil(length(s)/2)+1:l
s2=[s2,str2double(s(i))]
end
end

if sum(s1)==sum(s2)
tf = 1
else
tf = 0
end

Solution Comments

Solution 1022857

2 Comments

2 Comments

auto2060 on 19 Oct 2016

Inspired by solutions 205786

auto2060 on 19 Oct 2016

Inspired by solution 205786

Solution 898607

1 Comment

1 Comment

Jerivington on 30 May 2016

could be better

Solution 244248

1 Comment

1 Comment

Niklas Nylén on 31 May 2013

I just wanted to see if this would be accepted. I can't find a way to remove it...

Solution 205786

1 Comment

1 Comment

Hassan Javaid on 18 Sep 2013

can you please explain what is going on inside dot function and why the str input?

Solution 174149

1 Comment

1 Comment

sea knowledge on 13 Dec 2012

in this code,it seems that end/2 is not alwayss an integer,so we need modify it,l wonder your code works or the workspace report a warning

Solution 158171

1 Comment

1 Comment

Jerome on 20 Jan 2013

That is cheating :P

Solution 148515

1 Comment

1 Comment

Tarun(TJ) Jhamnani on 26 Oct 2012

nicely done..

Solution 112271

1 Comment

1 Comment

Joseph Kirk on 17 Dec 2012

Excellent way to use the dot product. Wish I would have thought of it!

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Problem 74. Balanced number

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Problem 74. Balanced number

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