Excel I/o matlab
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The attached Distances.xlsx file contains a spreadsheet with the pairwise distances in miles of the top 100 US cities by population. A preview of the spreadsheet is shown below. The first row and first column contain the city names using the following format: city name comma space capitalized state abbreviation, e.g., Nashville, TN. Note that the very first cell of the spresheet, A1, is blank. Write a function called get_distance that accepts two character vector inputs representing the names of two cities. The function returns the distance between them as an output argument called distance. For example, the call get_distance('Seattle, WA','Miami, FL') should return 3723. If one or both of the specified cities are not in the file, the function returns -1. Preview of the first five cities of Distances.xlsx
20 Comments
Walter Roberson
on 24 Mar 2019
We are already discussing this at https://www.mathworks.com/matlabcentral/answers/445405-assignment-question-based-on-excel-file-i-o#comment_684611 where you have already been given a fair bit of assistance, along with the one major hint that you need to solve the problem in the code you had posted.
Priyamvada Shankar
on 24 Mar 2019
Walter Roberson
on 24 Mar 2019
You have a vector of values that are the result of strcmp. What happens if you any() the vector ? What does that mean?
Sanket khullr
on 2 Apr 2019
Edited: per isakson
on 12 Jun 2019
function distance = get_distance(a,b)
[~,text,raw] = xlsread('Distances.xlsx');
for i=2:size(text,1)
if strcmp(text{i,1}, a)
break
end
end
if strcmp(text{i,1}, a)
x=i;
else
distance=-1;
end
for j=2:size(text,2)
if strcmp(text{1,j}, b)
break
end
end
if strcmp(text{1,j}, b)
distance= raw{x,j};
else
distance=-1;
end
Sanket khullr
on 2 Apr 2019
Edited: per isakson
on 12 Jun 2019
This is the correct matlab code
Walter Roberson
on 2 Apr 2019
No. If a is not found but b is found, then you do not set the value of x to anything, but you still try to use raw{x,j}
Yueqi Li
on 16 Apr 2019
Could you please tell me how can I correct this problem?
Walter Roberson
on 16 Apr 2019
There are many approaches.
One of the approaches is to initialize distance to -1. If it does not get changed, then it will still be that when you return. Then, as soon as you find the appropriate match on the two parts, set distance appropriately, and return from the function.
sujhan vikram
on 12 Jun 2019
Edited: sujhan vikram
on 13 Jun 2019
function distance = get_distance(x,y)
[~,~,raw] = xlsread('Distances.xlsx');
[a b]=size(raw);q=0;w=0;
for i = 2:a
if contains(raw{i,1},x)==1
q=i;
end
end
for j = 2:b
if contains(raw{1,j},y)==1
w=j;
end
end
if q>0 && w>0
distance = raw{q,w};
else
distance = -1;
end
sujhan vikram
on 12 Jun 2019
Edited: sujhan vikram
on 13 Jun 2019
Whats the mistake ??
Walter Roberson
on 12 Jun 2019
What error are you encountering?
per isakson
on 12 Jun 2019
"The attached Distances.xlsx" Where is it?
sujhan vikram
on 13 Jun 2019

sujhan vikram
on 13 Jun 2019
Edited: sujhan vikram
on 13 Jun 2019
there seems to be 'north las vegas' and 'las vegas' in the .xls file and north las vegas comes first from top so my code chooses it.
corrected it by running the for loop from bottom ie.(a to 2).
madhan ravi
on 13 Jun 2019
Where is the data file?
Jaimin Motavar
on 2 Jul 2019
you should use strcmp function instead of contains.
function distance = get_distance(x,y)
[~,~,raw] = xlsread('Distances.xlsx');
[a b]=size(raw);q=0;w=0;
for i = 2:a
if strcmp(raw{i,1},x)==1
q=i;
end
end
for j = 2:b
if strcmp(raw{1,j},y)==1
w=j;
end
end
if q>1 && w>1
distance = raw{q,w};
else
distance = -1;
end
Deep Raj Bhujel
on 19 May 2020
Thank you Jaimin.
nicola Braham
on 29 Aug 2020
why do you need the if q>1 && w>1 line? isn't that a given?
nicola Braham
on 29 Aug 2020
is it just because the first row and first column contain city names not distances?
Walter Roberson
on 29 Aug 2020
Neither q nor w are given (not passed in by the user, not prompted for). Both of them are calculated.
Notice this particular part of the assignment:
"If one or both of the specified cities are not in the file, the function returns -1."
Therefore we cannot assume that the cities passed in will definitely be in the file, so we cannot assume that the positions q or w will have been set to valid values. Testing q and w is checking to be sure that the cities were actually found.
Answers (5)
Sravani Kurma
on 28 Jul 2020
Edited: Sravani Kurma
on 28 Jul 2020
code with explaination:
function distance=get_distance(alpha,beta)
[~,~,d]=xlsread('Distances.xlsx');% to read values
[m,n]=size(d);% to find the size of d interms of matrix dimensions mxn
s=strcmp(alpha,d(1,1:n));% comparing each string of one row of sheet with given name of the city say alpha
p=(sum(s==1));% aftr comparing output will be logical 1 or 0, so, we get max one logical 1 value and all other zeros ,so sum will be 1+n(0)=1
if p==0 %if p==0,no matching city,,,
distance= -1;
return
end
t=strcmp(beta,d(1,1:m));
q=(sum(t==1));
if q==0
distance= -1;
return
end
distance=d{find(s==1),find(t==1)};%find will given the index value of t==1 and s==1
4 Comments
Walter Roberson
on 28 Jul 2020
p=(sum(s==1));% aftr comparing output will be logical 1 or 0, so, we get max one logical 1 value and all other zeros ,so sum will be 1+n(0)=1
That is not "perfect". You could simply ask any(s) instead of doing that summation.
Sravani Kurma
on 28 Jul 2020
Edited: Sravani Kurma
on 28 Jul 2020
Yeah,I agree with your suggestion also...but may I know any problem in using my logic of addition? Because i tested the code and it's working fine...
Rik
on 28 Jul 2020
There is nothing wrong with the code, but it is not optimal or intuitive, and therefore not perfect. Compare the two blocks below. For positive integer values of b they will have the same result, but one is clearly better.
a+b
for n=1:b
a=a+1;
end
Sravani Kurma
on 28 Jul 2020
Ok..tq
Irfan Hussain
on 1 Apr 2020
function distance = get_distance(city_1 , city_2)
[num,txt,raw] = xlsread('Distances.xlsx');
p = 0; q = 0;
name_1 = strcmpi(city_1,raw(:,1));
p = find(name_1 == 1);
name_2 = strcmpi(city_2,raw(1,:));
q = find(name_2 ==1);
if p > 1 && q > 1
distance = raw{p, q};
else
distance = -1;
end
6 Comments
Walter Roberson
on 1 Apr 2020
You do not use name_1 or name_2 except in the immediately following line, so it would probably make more sense to use
p = find(strcmpi(city_1, raw(:,1)) == 1);
Now, strcmpi() returns logical 0 (false) and logical 1 (true), and find() searches for non-zero values, so this in turn could be done more compactly as
p = find(strcmpi(city_1, raw(:,1)))
Question for you:
if p > 1 && q > 1
Under what circumstances could p be exactly 1, or less than 1 ?
Irfan Hussain
on 1 Apr 2020
yes you are right. basically the output give correct that i will past it in hurry. now i am improving the problem, i face non-existance city issue

Walter Roberson
on 1 Apr 2020
Edited: Walter Roberson
on 1 Apr 2020
- If X contains no nonzero elements or is empty, then find returns an empty array.
Notice this does not say that "if X containst no nonzero elements or is empty then find returns 0"
Also, in your logic, suppose that p or q were 0 so you set distance to -1. But then you go ahead and try to do
distance = raw{p,q};
anyhow, even though you already know that one of the cities was not found.
Sai kalyan Kolapally
on 18 May 2020
Edited: Sai kalyan Kolapally
on 18 May 2020
function distance= get_distance(a,b)
[~,~,all]=xlsread('Distances.xlsx');
p=0;q=0;
city1= strcmpi(a,all(1,:));
p=find(city1==1);
city2= strcmpi(b,all(:,1));
q= find(city2==1);
if isempty(p)==1 || isempty(q)==1
distance=-1;
else
distance= all{p,q};
end
end
Rohit Singh Chauhan
on 21 Sep 2020
function distance = get_distance(city1,city2)
[~, ~, everything] = xlsread('Distances.xlsx');
[row col] = size(everything);
c1 = 0;
c2 = 0;
for ii = [1:row]
c1_row = everything{ii,1};
if strcmp(c1_row,city1)
c1 = ii
end
end
for jj = [1:col]
c2_col = everything{1,jj};
if strcmp(c2_col,city2)
c2 = jj
end
end
if (c1==0 || c2==0)
distance = -1
else
distance = everything{c1,c2}
end
end
Lucero
on 24 Jun 2022
thanks
SAMARTH MAHESHKUMAR GEMLAWALA
on 15 May 2020
This is how i done it using for loop, make it simple to understand.
function distance = get_distance(a,b)
[num,txt,raw] = xlsread('Distances.xlsx');
x = size(raw)
v = a
c = b
for i=2:x(1,1)
y = raw{1,i};
if strcmp(y,v)
g=1
for j= 1:x(1,2)
z = raw{j,1};
if strcmp(z,c)
f=1
distance = raw{i,j};
break
else
distance = -1;
end
end
break
else
distance = -1;
end
end
1 Comment
manish Singh
on 20 Jun 2021
Brother can you elaborate your code
I am unable to understadnd, It will be very good if you add comment after every loop for better understanding
Mulayam Singh Choudhary
on 18 Jun 2020
Edited: Mulayam Singh Choudhary
on 18 Jun 2020
function distance=get_distance(a,b)
a= convertCharsToStrings(a);
b= convertCharsToStrings(b);
[bar,~,raj]=xlsread('Distances.xlsx');
ii=2;
for k=1:length(raj)-1
raj{1,ii}= convertCharsToStrings(raj{1,ii});
raj{ii,1}= convertCharsToStrings(raj{ii,1});
ii=ii+1;
end
ii=2;
jj=2;
for m=2:length(raj)
if raj{1,ii}==a
break;
end
ii=ii+1;
end
for n=2:length(raj)
if raj{jj,1}==b
break;
end
jj=jj+1;
end
if ii>length(raj)||jj>length(raj)
distance=-1;
else
distance=bar(jj-1,ii-1);
end
Prince Raj Yadav
on 26 Jul 2020
Get_Distance
function distance = get_distance(a,b)
[~,~,raw] = xlsread('Distance.xlsx');
[row,col] = size(raw);
for i = 2:row
if strcmp(raw{i,1},a) == 1
break;
else
i = 1;
end
end
for j = 2:col
if strcmp(raw{1,j},b) == 1
break;
else
j = 1;
end
end
if i > 1 && j > 1
distance = raw{i,j};
else
distance = -1;
end
end
1 Comment
Rik
on 26 Jul 2020
Same here. You don't add any comments, nor do you provide any reasons for the functions you're using. Why did you bother post this? (these are not meant as rhetorical questions)
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