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Evan


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Answered
Obtaining corresponding pixel indices in perspective-corrected image
I managed to find a solution to this problem. First note that this applies to MATLAB versions R2014b and earlier. While I can't ...

ungefär 9 år ago | 0

| accepted

Answered
Fibonacci sequence, slightly different.
It seems to be quite close. You just need to make one small change. You should reference the seq variable using the index, k, no...

mer än 9 år ago | 0

Answered
Extracting matrix diagonal with diag(A)
Does this fix your problem? a = eye(4,4) == 1; diag(a) While the *diag* function works fine, if you have a variable n...

mer än 9 år ago | 0

| accepted

Answered
Merge tables with different dimensions?
Does this example do what you need? A = randi(9,4,3) B = randi(9,4,5) C = randi(9,4,2) D(1:4,1:size(A,2)) = A;...

mer än 9 år ago | 0

Answered
search for a code in a cell
key = [1 1 -1 -1] C{1} = [1 1 1 1];C{2}=[1 1 -1 -1];C{3}=[1 -1 1 -1];C{4}=[1 -1 -1 1] loc = find(cellfun(@(x)all(x == ke...

mer än 9 år ago | 1

| accepted

Answered
I need help creating a function for taking an array and reversing it and i have to use a for loop. I have looked online but i really dont know what i am doing?
There are built-in functions for this, such as *fliplr* and *rot90*. However, if you want to use a loop, think about the proc...

mer än 9 år ago | 0

Answered
Difference Between a Number and Character Array
These links might be helpful for understanding data types in MATLAB, as well as classes in general: * <http://www.mathworks.c...

mer än 9 år ago | 0

Answered
When zooming, 3D plotted data exceeds uipanel extent despite axes being clipped
While I'm able to replicate this in previous MATLAB versions R2012a, R2012b, R2014a as well as some releases prior to 2011, this...

mer än 9 år ago | 0

| accepted

Answered
Most Efficient Spreadsheet File
If Image Analyst's solution doesn't work for you, you might try *csvread*. Assuming you're able to save your data in .csv format...

mer än 9 år ago | 0

Question


Obtaining corresponding pixel indices in perspective-corrected image
I am attempting to warp an image taken from an off-center camera to produce an image that resembles the viewfield were it taken ...

mer än 9 år ago | 1 answer | 0

1

answer

Answered
How to reverse a number?
x = 1234; s = num2str(x) - '0'; xr = polyval(s(end:-1:1),10)

mer än 9 år ago | 2

Answered
User Defined input in form of a table
You can either import tabular data from excel using *xlsread* or create a GUI that contains a *uitable* with MATLAB. Creating yo...

mer än 9 år ago | 0

| accepted

Answered
Counting element length in cells.
Look into <http://www.mathworks.com/help/matlab/ref/cellfun.html *cellfun*> >> A = {'Piggy'; 'gue7352892'; 'hdufhe~jf'}; ...

mer än 9 år ago | 9

Answered
switching pixel with defined colour in a matrix
If I is your image: I = imread('peppers.png'); R = I(:,:,1); G = I(:,:,2); B = I(:,:,3); Idx = reshape(randperm...

mer än 9 år ago | 1

| accepted

Answered
Random number generation after time interval
I'm assuming this program involves a loop. If so, is each iteration quick enough that it's sufficient to simply check how much t...

mer än 9 år ago | 0

Answered
Is it possible to make graphs like this in MATLAB?
Have you tried *boxplot*? http://www.mathworks.com/help/stats/boxplot.html

mer än 9 år ago | 0

Answered
How to store user-generated text within a loop?
In order to store multiple strings, likely of different lengths, you will need to use a cell array. <http://www.mathworks.com/he...

mer än 9 år ago | 0

| accepted

Answered
How can i get neighbors from 3D array but in the same order as the matrix ?
One way to do it: A = rand(5,5,5); B = false(size(A)); B(3,3,3) = true; %Point around which you want to find neighbor...

mer än 9 år ago | 0

Answered
how to ellipse fitting to connected object?
help regionprops This allows you to return the orientation, major axis length, and minor axis length of binary data with r...

mer än 9 år ago | 0

| accepted

Answered
How to draw a two y axis and one x axis graph . The Two y axis should arrange in top and bottom and x axis should position in left side of the plot
If *plotyy* doesn't work for your purposes, you can create two axes with the same position, then set the 'Color' property of the...

nästan 10 år ago | 0

Answered
code to form a matrix by selecting some elements in another matrix
Look into the *randi* function.

nästan 10 år ago | 0

| accepted

Answered
Problem in plotting a summation
Try out the *cumsum* function. Also it's worth noting that all the functions/operators you need (factorial, ./, .^, etc.) can al...

nästan 10 år ago | 0

Answered
for loop for matlab files
% where N is the number of files for i = 1:N load(['M' num2str(N) '.m']) end This will change based on whether...

nästan 10 år ago | 0

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Answered
How to write program to choose random numbers from given input set?
see *randi*

nästan 10 år ago | 0

Answered
How to navigate through Struct/Cell from Matlab Gui?
For determining the datatype of the arrays selected by the user, see the *iscell* and *isstruct* functions. The *who* command ca...

nästan 10 år ago | 0

Answered
Plot doubt: how to fill the squares.
Try using the *MarkerFaceColor* property. Example: x = 0:pi/32:2*pi; y = sin(x); z = cos(x); plot(x,y,'s',x,z,'...

nästan 10 år ago | 0

| accepted

Answered
How to know time that spent matlab in solving problem?
help profile or help tic Running *tic* and *toc* will simply tell you how much time passed between the respective ...

nästan 10 år ago | 0

Answered
Easy for loop question
i must be a real, *positive* integer. Because i starts at 1, and you reference A(i-1,2), your first iteration will try to access...

nästan 10 år ago | 1

Answered
How to retain only the positive root of a quadratic equation?
help imag So, if you wanted to return only roots without complex parts: R_all = roots([1 1 0 1]); R_real = R_all(~i...

nästan 10 år ago | 1

Answered
How to accept an answer in a comment?
If you can't get them to re-submit it themselves, and if flagging doesn't work, I would just copy+paste it into an answer of you...

nästan 10 år ago | 0

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