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矩阵的符号运算结果如何简化?。
你这是自己给自己找麻烦。 前面第一次给 k 矩阵赋值,它是个只与 l 变量有关的矩阵,而你最后是要把具体数值代入 l 变量的,所以 k 矩阵实际就是个数值矩阵。 随后 k = EI/l*k; 这句,EI是可以当做一个因数或者系数,单独提出来的,剩余的 ...
mer än 2 år ago | 0
| accepted