The nth element of a series A is defined by: 
. Obviously, the first element 
. Given the nth element 
, find the value of the corresponding index n.
. Obviously, the first element . Given the nth element , find the value of the corresponding index n.Solution Stats
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@Ramon, if you are submitting a question on Cody for everybody to solve, it is recommended you put atleast 3 test suites, mostly so that it encourages people to learn and not hard code solutions.
Thanks, @Dyuman. There are now 4 test suites.
@Ramon, Wonderful!
-a+(1-(-1)^(n+1))/2 will be negative in the 4th test. I believe it should be: index(a-(1-(-1)^(n+1))/2).
This works fine in my MATLAB software. But not here.
Any comments, please?
function n = index(a)
for idx = 1:1000
b = idx*((-1)^(idx^3+1));
if b==a
break
else
continue
end
end
n=idx;
end
Because you are not doing what the question is asking
I think the last test case is wrong
Rahul Gulia, in the last test, there will be numbers greater than 1000. And the last test is not wrong. Just remember that indexes are always positive (I had trouble with that also, we are so focused on the sequence that we forget that indexes can't be negative).