Maybe some tests with more than two distincts subgraphs.
Seems the problem became easier with R2015b.
very cool (and efficient) solution
Equidistant numbers containing certain value in an interval
Hackathon: the beginnings
Make a Star Pyramid
Make a diamond
Generate a NaN...on purpose
2048 Next Move
Crossing to Kissing - Untangle the Lines
Eliminate Polysyllabics: Long live short words!
Twins in a Window
Would Homer Like It?
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