In a parallel universe the gravity works very strangely.
Indeed, gravity is equal to: g = sin( (pi/2)*t/60 ) [m/s^2], where t is the time expressed in seconds, and it acts along the direction normal to the ground.
At time t = 0 seconds, a ball is at height y = 1 meter and has zero velocity. What is the position y (meters) of the ball as a function of time (seconds)?
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Chris Cleveland Dyuman Joshi Christian Schröder Lorenzo

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