Problem 42891. Differential equation and events
41.18% Correct | 58.82% Incorrect
Last Solution submitted on Jun 04, 2023
Tim on 14 Jun 2016
It looks like [y;y']=[a,b] would mean y(0)=a and y'(0)=b, but a first order differential equation should have one initial condition y(t0)=y0.
hubert andre on 14 Jun 2016
Thanks Tim, yes, I did a mistake in the equation, its a 2nd order.
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