Negative surface area??
Cmon I'm sure a bit more challenging problems would'nt harm the a players brain...
I would have preferred something a bit more challenging, like asking for the volume, given the surface area, rather than just the radius. Then, the two-step solution (solve for r from area, and volume from r) could be consolidated into one line (by raising the area amount to the 1.5 power and scaling the constants appropriately).
I don't know why the lead solution is like this with the regular expression. And i estime the time with tic and toc. It is not the best. What is the size here? can anybody tell me, thx.
dis probm is swwet yo i rly liekd i
Can anybody tell me what this question means? thx :)
Given Surface Area of Sphere. Find Radius of Sphere
This user (mohamed elbesealy) appears to have gamed the system, with fraudulent "likes" of this unremarkable solution submitted by 'sock-puppet' accounts. —DIV
Im sorry what is x, the volume or the radius.
Why is the size 2 for this solution?
This funciton fails the assertions when I run it, and it becomes size 14. I am confounded.
I am a bit bewildered about the size too. According MathWorks, it ought to be higher due to the inspection algorithm (see <>).
Remove the polynomials that have positive real elements of their roots.
Get the area codes from a list of phone numbers
Project Euler: Problem 1, Multiples of 3 and 5
middleAsColumn: Return all but first and last element as a column vector
ベクトル [1 2 3 4 5 6 7 8 9 10] の作成
Acidity of vinegar and salts
Multiply a column by a row
Generate one sample of uniform random numbers between -pi and +pi
Surface Fit z(x,y)
Find the treasures in MATLAB Central and discover how the community can help you!
Choose a web site to get translated content where available and see local events and offers. Based on your location, we recommend that you select: .
You can also select a web site from the following list:
Select the China site (in Chinese or English) for best site performance. Other MathWorks country sites are not optimized for visits from your location.
Contact your local office