How to draw exponential function in matlab

Does anyone know how to draw this function f(x)=sin(x). Exp(-lxl) in Matlab?Thanks.

Answers (2)

It seems like you listed a couple of functions, were you looking to plot them separately?
Can plot the functions using fplot
nexttile
fplot(@(x)sin(x))
nexttile
fplot(@(x)exp(-abs(x)))
Or plot values using plot
nexttile
x=linspace(-5,5,100);
plot(x,sin(x))
nexttile
plot(x,exp(-abs(x)))

8 Comments

How to merge it?
I mean how to draw f(x)=sin(x). Exp(-lxl),not seperately thanks
I'm not sure what 'merge it' means...on the same axes?
fplot(@(x)sin(x))
hold on
fplot(@(x)exp(-abs(x)))
I mean how to draw f(x)=sin(x)*Exp(-lxl) thanks
Is there something in particular that's difficult about changing the equation?
fplot(@(x)sin(x).*exp(-abs(x)))
what does nexttile mean?
Hi Chris, can you expand on your question a bit?
nexttile means to move to the next sub plot. It is a more modern way of using subplot() that has some advantages.

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Thanks,How to define the area of X from minus 10 to plus 10

5 Comments

Chris Lin
Chris Lin on 8 Aug 2021
Edited: Chris Lin on 8 Aug 2021
How to find the integral of y(x)=sin(x)*Exp(-lxl)*exp(-i k x). Integration range from x=-10 to x=10, k=2
format long g
k = 2
k =
2
y = @(x) sin(x).*exp(-abs(x)).*exp(-i.*k.*x)
y = function_handle with value:
@(x)sin(x).*exp(-abs(x)).*exp(-i.*k.*x)
syms x
area_sym = simplify(int(y(x), x, -10, 10))
area_sym = 
double(area_sym)
ans =
0 - 0.400020854904531i
area_numeric = integral(y, -10, 10 )
area_numeric =
1.02753566831419e-17 - 0.400020854904531i
How to calculate when k=1?
format long g
y = @(x,k) sin(x).*exp(-abs(x)).*exp(-i.*k.*x)
y = function_handle with value:
@(x,k)sin(x).*exp(-abs(x)).*exp(-i.*k.*x)
syms x k
area_sym = simplify(int(y(x,k), x, -10, 10))
area_sym = 
area_k_sym = simplify(subs(area_sym,k,(1:8).'))
area_k_sym = 
double(area_k_sym)
ans =
0 - 0.799941726389522i 0 - 0.400020854904531i 0 - 0.141179603605318i 0 - 0.0615282799753523i 0 - 0.0318073184754602i 0 - 0.0184532189656321i 0 - 0.0116468126495915i 0 - 0.00780451904492856i

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Asked:

on 7 Aug 2021

Commented:

on 11 Aug 2021

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