Save 360 arrays in a cell
Show older comments
Hello,
My programs loads 360 images (laser stripe) and from each image gets the 0 crossing of all rows. My issue is that after processing all images, im not able to save the 0 crossing arrays into a cell so I can post process them. Here my code:
clc; clear all; close all;
%% CARGAR LAS IMAGENES (load images)
for k = 1:360
jpgFilename = sprintf('%d.jpg', k);
fullFileName = fullfile('C:\MASTER\S2\percepcion\laser360\imagenes', jpgFilename);
if exist(fullFileName, 'file')
imageData = imread(fullFileName );
imageData=imrotate(imageData,90);
% se binariza la imagen (binarization)
img_o=rgb2gray(imageData);
mask=(img_o(:,:) > 50);
imageData = bsxfun(@times, img_o, cast(mask, 'like', img_o));
% figure()
% imshow(imageData)
% title('Binarizada')
%
[rows, columns, numberOfColorChannels] = size(imageData);
img_peaks = NaN(rows, 1);
img_puntos = zeros(rows, columns);
Xp = [];
Yp = [];
Xn=[];
Yn=[];
m=[];
n=[];
zerocross=[];
coefficients=[];
lineaslaser=cell(k,1);
%se busca la linea del 0 crossing
for icross=1:rows
img_puntos(icross,:)=imageData(icross,:);
%filtrado
filtrado=sgolayfilt(double(img_puntos(icross,:)),3,33 );
for ks=1:length(filtrado)
if filtrado(ks)<0
filtrado(ks)=0;
end
end
%derivada (gradient)
derivada=gradient(filtrado);
%maximo y minimo
[Yp(icross),Xp(icross)]=max(derivada);
[Yn(icross),Xn(icross)]=min(derivada);
%coeficientes de la recta (line coefs)
m(icross)= (Yp(icross)-Yn(icross))/(Xp(icross)-Xn(icross));
n(icross)= (Yp(icross)-m(icross)*Xp(icross));
% 0 crossing
zerocross(icross)= -n(icross)/m(icross);
img_peaks(icross) = zerocross(icross);
end
axis=1:1920;
img_peaks((1:10),1)=NaN;
img_peaks((1500:1920),1)=NaN;
% save 360 lines in a cell
lineaslaser{k}=img_peaks(k);
% figure()
% plot(axis,img_peaks)
% title('plot perfil de la pieza (0 crossing)')
else
warningMessage = sprintf('Warning: image file does not exist:\n%s', fullFileName);
uiwait(warndlg(warningMessage));
end
end
3 Comments
What exactly is the problem? Should I guess?
You're saving a single element from a numeric vector into a cell vector. Are you expecting to be saving the entire vector?
lineaslaser{k}=img_peaks(k);
Considering that you do this right before that assignment, the first 10 entries in lineaslaser will be scalar NaNs.
img_peaks((1:10),1)=NaN;
But none of that really matters, because every time the loop cycles, you delete the entire array:
lineaslaser=cell(k,1);
If you know the size of the arrays needed, preallocate them as the required size instead of growing them in a loop.
Xp = [];
Yp = [];
Xn=[];
Yn=[];
m=[];
n=[];
mikel lasa
on 15 Apr 2021
DGM
on 15 Apr 2021
Okay. If you move the preallocation outside the main loop and set that line to
lineaslaser{k}=img_peaks;
does it help?
Accepted Answer
More Answers (0)
Categories
Find more on Creating and Concatenating Matrices in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!