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How do i make this code as simple as possible? :(

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final_0 = 0;
final_1 = final(numel(final_0)+1:(floor(numel(final)*1/10))*1);
final_2 = final(floor(numel(final)*1/10)*1+1:floor(numel(final)*1/10)*2);
final_3 = final(floor(numel(final)*1/10)*2+1:(floor(numel(final)*1/10))*3);
final_4 = final(floor(numel(final)*1/10)*3+1:(floor(numel(final)*1/10))*4);
final_5 = final(floor(numel(final)*1/10)*4+1:(floor(numel(final)*1/10))*5);
final_6 = final(floor(numel(final)*1/10)*5+1:(floor(numel(final)*1/10))*6);
final_7 = final(floor(numel(final)*1/10)*6+1:(floor(numel(final)*1/10))*7);
final_8 = final(floor(numel(final)*1/10)*7+1:(floor(numel(final)*1/10))*8);
final_9 = final(floor(numel(final)*1/10)*8+1:(floor(numel(final)*1/10))*9);
final_10 = final(floor(numel(final)*1/10)*9+1:floor(numel(final)));
I think anyone who has studied a little bit can make it simple, but I'm not
For your information, the class of those codes is char.
The size of one data is so large that you want to split it into 10 pieces.
Please let me know, and if you have time, I would like to know if this code can be expressed in loop. :((((((((

Accepted Answer

Ameer Hamza
Ameer Hamza on 30 Dec 2020
First, naming variables like final_1, final_2, ... is a bad coding practise: https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval. Always use arrays. In your case, cell arrays are most appropriate.
You can write the code in a single line like this
final = .. % your arrat
final_split = mat2cell(final, 1, numel(final)/10*ones(1,10))
  5 Comments
Ameer Hamza
Ameer Hamza on 31 Dec 2020
Edited: Ameer Hamza on 31 Dec 2020
Just use indexing to access each element of the cell array. There is no need to create seperate variables. For example
final_split{1} % access first element
final_split{2} % access second element
..
..
final_split{end} % access last element
Jungwu Kim
Jungwu Kim on 31 Dec 2020
thank you!! god bless you and happy new year~

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More Answers (1)

Walter Roberson
Walter Roberson on 30 Dec 2020
buffer(final, floor(numel(final)/10)).'
Needs the signal processing toolbox.
The final (11th) row will contain 110227 entries only the first two of which will be nonblank. You might want to consider using ceil instead of floor which will get you 10 rows the last of which has 8 padding positions.

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