Date Parsing Error for Time 00:00:00 from MS Excel
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Dears,
I am using the code below to do parsing for date-time cells in an MS Excel sheet with date-time form of ( 01/05/2019 00:00) as in the screenshot below.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/389248/image.jpeg)
clc,clear,close all;
[num1,data] = xlsread('Book_new.xlsx','sheet1','A1:A30');
a=datevec(data,'dd/mm/yyyy HH:MM:SS');
date=datestr(datenum(a),'dd/mm/yyyy');
time=datestr(datenum(a),'HH:MM:SS');
Year=datestr(datenum(a),'yyyy');
mm=datestr(datenum(a),'mm');
dd=datestr(datenum(a),'dd');
yy=datestr(datenum(a),'yyyy');
[status,message] =xlswrite('motasem.xlsx',str2num(yy),'sheet1','A1:A30');
[status,message] =xlswrite('motasem.xlsx',str2num(mm),'sheet1','B1:B30');
[status,message] =xlswrite('motasem.xlsx',str2num(dd),'sheet1','C1:C30');
[status,message] =xlswrite('motasem.xlsx',string(time),'sheet1','D1:D30');
When I run the code for example for the 1st 30 readings (half hourly readings) it gives me the following error :
"Error using dtstr2dtvecmx
Failed to convert from text to date number.
Error in datevec (line 123)
y = dtstr2dtvecmx(t,icu_dtformat);
Error in motasem (line 4)
a=datevec(data,'dd/mm/yyyy HH:MM:SS');"
But when I change the range of data to avoid the first reading which contains the time 00:00:00 it works and gives the below output :
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/389253/image.jpeg)
Any suggestions please ?
2 Comments
Answers (1)
Motasem Mustafa
on 23 Oct 2020
3 Comments
Peter Perkins
on 18 Nov 2020
Yes, as Walter says, don't use datenum. There are datetime methods like year and ymd for all of those things you are exporting. You do not need to convert datetimes to datenums, to datestrs, to numeric.
Also, I strongly recommend that you look at writetable instead of xlswrite. Create separate y/m/d and time of day variables in the table, and you can write it all out in one line.
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