How to make a structure unique?

emp.x=[]; 
emp.info=[];
emp.fit=[]; 
pop=repmat(emp,1,1);

pop(1).x=[1 2 3 4];
pop(2).x=[3 2 1 4];
pop(3).x=[1 2 3 4];
pop(4).x=[2 1 3 4];

How to make the above structure (pop) unique?

The result would be like the following figure.

[Walter Roberson]

Will there ever be a case where the x values are not row vectors? Will there ever be a case when the row vectors are not the same length? For example will any of the entries ever be empty?

[Md. Asadujjaman]

X values are not a row vector.

Row vectors are the same length.

Here, the 'info' and 'fit' entities are empty. After making the structure (pop) unique, I will do some analysis and therefore the 'info' and 'fit' entities would not be empty.

It would be also helpful for if anyone can make the following structure (pop) unique.

emp.x=[];

pop=repmat(emp,1,1);

pop(1).x=[1 2 3 4];

pop(2).x=[3 2 1 4];

pop(3).x=[1 2 3 4];

pop(4).x=[2 1 3 4];

Result wouldbe as follows:

[Walter Roberson]

X values are not a row vector.
Row vectors are the same length.

Which row vectors are the same length as each other if they are not the X values? (We know they are not the X values because you said that the X values are not row vectors.)

[Md. Asadujjaman]

sorry, X values are a row vector

Answer 1

[Rasul Khan]

You can achieve it using this script.

m = [];
for i = 1 : numel(pop)
    m = [m ; pop(i).x];
end
[~ , ia , ~] = unique(m , 'rows');
pop = pop(ia);

[Walter Roberson]

m = vertcat(pop.x);
[~ , ia , ~] = unique(m , 'rows');
pop = pop(ia);

[Md. Asadujjaman]

Thank you. It's working.

I got the result.