How do I create a user generated matrix in Matlab?
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Hello,
I am a student who has been tasked with writing a program that asks the user to define how many rows and columns a matrix should have. After which point, the user will be again asked what values go in each cell of the matrix. Where I am having trouble, is figuring out how to take the number of rows and columns that a user defines, and turn that into a matrix.
This is what I have so far:
Rows = input('Please input the number of rows you would like to have: ');
disp(' ');
Columns = input('Please input the number of columns you would like to have: ');
disp(' ');
If, for example the user wanted a matrix with 1 row and 4 columns, how would I go about generating said matrix given the user input?
Edit: Is it possible to achieve what I am asking, without simply having a user input a whole matrix?
2 Comments
Mohsin
on 24 Sep 2022
Yes you can acheive without asking user, here is how
Matrix = randi([3,10],3,3)
It will create a matrix of order 3x3 and of number between 3 and 10
Feza Güngör
on 28 Nov 2023
useful bro, thanks !
Accepted Answer
More Answers (3)
a = input('Enter the number of rows');
b = input('Enter the number of coloumns');
for i=1:a
for j=1:b
p(i,j)=input('Enter the elements');
end
end
p=reshape(p,a,b)
1 Comment
Sarah
on 26 Feb 2023
is there a way to combine this into on statment for example [x,y] = input('Enter rows and columns')
JEERU
on 29 Sep 2023
0 votes
a = input('Enter the number of rows');
b = input('Enter the number of coloumns');
for i=1:a
for j=1:b
p(i,j)=input('Enter the elements');
end
end
p=reshape(p,a,b)
Aryan
on 8 Aug 2024
0 votes
a = input('Enter the number of rows');
b = input('Enter the number of coloumns');
for i=1:a
for j=1:b
p(i,j)=input('Enter the elements');
end
end
p=reshape(p,a,b)
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