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Convert table and obtain column values

Asked by Collegue on 13 Sep 2019
Latest activity Answered by Steven Lord
on 18 Sep 2019
Hello, I have this table
Captura.PNG
How can I first generate an array of string and numbers and then replace the '---' with NaN. Finally I would need to get the values of the Var4 and Var 7.

  2 Comments

Have you check here readtable?
Yes I have conberted to table and that is the table that i have obtained.

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2 Answers

Answer by Jalaj Gambhir on 16 Sep 2019
 Accepted Answer

Hi,
For the particular task one possible solution could be by first converting the table to cell array using table2cell. And then traversing through the structure to search for ‘- -’ and replacing it with NaN
T = cell(CellArray);
for i=1:length(CellArray)
for j= 1:length(CellArray{1})
if ~isequal(CellArray{i,j},'--')
T{i,j} = CellArray{i,j};
else
T{i,j} = NaN;
end
end
end
R = cell2table(T);
And finally access the 4th and 7th column from the table by:
R(:,[4,7])

  1 Comment

Thank you very much1!! it works!!

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Answer by Steven Lord
on 18 Sep 2019

Use ismissing to locate the missing values (you can tell ismissing what it should consider as a missing value) then use the logical array output to replace the missing values with whatever value you want.
The fact that you're changing the data type (potentially for some but not all of the values of a table variable) could complicate things a bit, but if that's the case show a larger sample of your table (maybe two or three rows that have a missing value and two or three that don't) and we may be able to help you determine how to handle that situation.

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