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If else problem for year

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Write a function called valid_date that takes three positive integer scalar inputs year, month, day. If these three represent a valid date, return a logical true, otherwise false. The name of the output argument is valid. If any of the inputs is not a positive integer scalar, return false as well. Note that every year that is exactly divisible by 4 is a leap year, except for years that are exactly divisible by 100. However, years that are exactly divisible by 400 are also leap years. For example, the year 1900 was not leap year, but the year 2000 was.
valid = valid_date(2018,4,1)
valid = valid_date(2018,4,31)

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RAHUL ANTIL
RAHUL ANTIL on 14 Jun 2019
I know this is my homework but I've tried my best. I'm getting problem in leap year part.
Rik
Rik on 14 Jun 2019
Have you seen my answer below? Also, what is your problem with determining if a year is a leap year? If you don't know about it yet: the mod function could be very helpful.
RAHUL ANTIL
RAHUL ANTIL on 14 Jun 2019
Here is my function-
I need help that if non-scalar value is used then ouput is false.
function valid = valid_date(year,month,day)
if (isinteger(year/4) || ~isinteger(year/4)) && ((month == 1) || (month == 3) || (month == 5) || (month == 7) || (month == 8) || (month == 10) || (month == 12)) && (day>0 && day<=31)
valid = true;
elseif (isinteger(year/4) || ~isinteger(year/4)) && ((month == 4) || (month == 6) || (month == 9) || (month == 11)) && (day>0 && day<=30)
valid = true;
elseif mod(year, 400) == 0 && month == 2 && (day>0 && day<=29)
valid = true;
elseif mod(year, 4) == 0 && mod(year, 100) ~= 0 && month == 2 && (day>0 && day<=29)
valid = true;
elseif ~(mod(year, 400) == 0) && month == 2 && (day>0 && day<=28)
valid = true;
elseif ~(mod(year, 4) == 0 && mod(year, 100) ~= 0) && month == 2 && (day>0 && day<=28)
valid = true;
else
valid = false;
end

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Accepted Answer

James Tursa
James Tursa on 14 Jun 2019
Edited: James Tursa on 14 Jun 2019
All of those if-elseif blocks make the code difficult to read, and difficult to debug as well. I would advise against that approach, and instead tackle each issue one at a time and code only for that issue. That makes the logic of each test much easier to read and to debug. For example, here is an outline of what the code could do using words:
function valid = valid_date(year,month,day)
valid = false; % Set a default return value
% Check for positive integer scalar inputs
if( the year is not a positive integer scalar )
return;
end
if( the month is not a positive integer scalar )
return;
end
if( the day is not a positive integer scalar )
return;
end
% Check for proper month
if( the month is not between 1 and 12 inclusive )
return;
end
% Construct an array of the number of days in each month
days_in_month = a 12-element array of the number of days in each month;
% Check to see if this is a leap year
is_leap_year = (you put some code here to determine if the year is a leap year)
% If it is a leap year, change February number of days to 29
if( is_leap_year )
Change the days_in_month value for February to 29
end
% Check to see if the day number is valid
if( the day is greater than the number of days in the month )
return;
end
% Passed all of our checks, so the date must be valid
valid = true;
return;
end
Once you are satisfied that the words do what you want (you should check this yourself ... maybe I missed something that needs to be checked), then you need to write actual code for all of the worded places. The code you write for this outline will in many places be pieces of the code you have already written in your if-elseif blocks above.

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Ashwin Raju
Ashwin Raju on 27 Feb 2020
Thank you for the help but still not able to get the output. I even tried 'd > b(m)' instead of 'd > b' among a lot of other things.
MOHD FARHAN
MOHD FARHAN on 7 Jun 2020
This is showing error please help
Rik
Rik on 7 Jun 2020
What did you try? The code posted in this answer is not the finished code you can hand in. It is meant as a guide to help you get a solution on your own.

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More Answers (4)

Salman P H
Salman P H on 28 Apr 2020
function valid = valid_date(x,y,z)
t = (isscalar(x) && isscalar(y) && isscalar(z));
if t==false
valid = false;
return;
end
if (x<=0 || y<=0 || z<=0)
valid = false;
return;
end
if any(rem([x, y, z], 1))
valid = false;
return;
end
if (((rem(x,4)==0) && (rem(x,100)~=0)) || (rem(x,400)==0))
a=1;
else
a=0;
end
if (x>0) && a==1
if (y==1 || y==3 || y==5 || y==7 || y==8 || y==10 || y==12) && (z>0 && z<=31)
valid = true;
elseif (y==4 || y==6 || y==9 || y==11) && (z>0 && z<=30)
valid = true;
elseif (y==2 && (z>0 && z<=29))
valid = true;
else
valid = false;
end
elseif x>0 && a==0
if (y==1 || y==3 || y==5 || y==7 || y==8 || y==10 || y==12) && (z>0 && z<=31)
valid = true;
elseif (y==4 || y==6 || y==9 || y==11) && (z>0 && z<=30)
valid = true;
elseif (y==2 && (z>0 && z<=28))
valid = true;
else
valid = false;
end
end

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Muthu Dhanush Santh Nagarajan
Edited: Rik on 9 Apr 2020
I have tried this program and i got all the answers correct. Please check
function valid=valid_date(y,m,d)
valid = false;
if(((isscalar(y) && y>=1 && y==fix(y))&& (isscalar(m) && m>=1 && m==fix(m) && m<=12)...
&& (isscalar(d) && d>=1 && d==fix(d) && d<=31))==1)
c1= (ismember(m,[4,6,9,11]) && ismember(d,[1:30]));
c2=(ismember(m,[1,3,5,7,8,10,12]) && ismember(d,[1:31]));
if ((c1==1 || c2==1)==1)
valid = true;
else
if ((mod(y,4)==0&&mod(y,100)~=0 || mod(y,400)==0&&mod(y,100)==0)==1)
if (ismember(d,[1:29])==1)
valid = true;
end
return;
else
if (ismember(d,[1:28])==1)
valid = true;
end
return;
end
end

  2 Comments

Rik
Rik on 9 Apr 2020
This function is missing documentation.
And what are the exact requirements of your assignment? You should try to create a test-suite that contains syntaxes that should work and return truie or false, and sytaxes that should return an error.
Also, do you have a question? Because you posted this in the answer section.
Mohammad Aiyoob Rahmani
Mohammad Aiyoob Rahmani on 18 Jun 2020
this code is right
it is working properly

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Rik
Rik on 13 Jun 2019
You can do this two ways:
Option 1 is to do the actual work. Is the input correct? Does the month entered actually have at least as many days as the day input (taking leap years into account)?
Or option 2: cheat by using the builtin functions to convert your input to a datetime scalar, and extract the year,month,day numbers from that. If those match the input, your date is valid. You should still put in a check if the inputs are positive scalars.

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Rik
Rik on 24 Jun 2019
Why are you using neither my suggestion, nor James's?
Also, this is input checking, which you should do before any other processing. Read about the numel function
Divya Nangaru Sudhakar
Divya Nangaru Sudhakar on 24 Jun 2019
I tried executing that function explained by James's, I dint get the output. Can you please help me with this function.
Thank you
Rik
Rik on 24 Jun 2019
James didn't provide a full function, because it is a homework exercise. If you want me to make your homework, first make sure I'll get the points from your teacher. (You can find guidelines for posting homework on this forum here.)
Did you read the documentation for numel? And how did you try to implement either my solution or the solution by James?

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MOHD FARHAN
MOHD FARHAN on 7 Jun 2020
Can anyone please give me the correct and accepted ans of this question please

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Rik
Rik on 7 Jun 2020
Why should other people do your homework?
Also, why did you post this in the answer section?

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