Could anyone help me to solve the following issue

Code:

a = [1 2 3 4 5;
     6 7 8 9 10]
a_rand = a(randperm(length(a)))

When i run the above two commands it executes and gives the following result

a_rand =     3     6     2     7     1

But in this result i can get only one row .

Coud anyone help me how to get two rows with the left out numbers displaying at the second row.

Answer 1

[KSSV]

a = [1 2 3 4 5;
     6 7 8 9 10] ;
idx1 = (randperm(length(a))) ;
idx2 = setdiff(1:numel(a),idx1) ;

iwant = [a(idx1) ; a(idx2)]

[jaah navi]

ok.with respect to two rows it works.But how it can be for n number of rows.

for the following matrix

a=[ 4.7908 5.0104 5.1329 5.3186 5.3094 5.3070 5.4452 5.5001;

0.0958 0.0994 0 0 0.1848 0.2020 0.1851 0.2146;

0.0848 0 0.1469 0.1859 0.1767 0.1854 0.1856 0.1648;

0 0 0 0 0 0 0 0;

0 0.0896 0.1619 0.1351 0 0 0 0;

0 0 0 0 0 0 0 0] .

Could you please help me on it.

[KSSV]

   iwant =  reshape(a(randperm(numel(a))),size(a)) ;

[jaah navi]

reshape should be done with respect to the elements present in its own column.But when i used the above command it reshapes with respect to different column.could you please help me to solve this.

[KSSV]

[m,n] = size(a) ; 
b = a ; 
for i = 1:m
    idx = randperm(n) ; 
    b(i,:) = a(i,idx) ;
end
    

Answer 2

[TADA]

a = [1 2 3 4 5; 6 7 8 9 10]
a_rand = a(randperm(length(a)))
a_rand = [a_rand; a(~ismember(a(:),a_rand(:)))']

[jaah navi]

It works fine for two rows,but how it can done for n number of rows with repect to the above mentioned matrix

a=[4.7908    5.0104    5.1329    5.3186    5.3094    5.3070    5.4452    5.5001;
    0.0958    0.0994         0         0    0.1848    0.2020    0.1851    0.2146;
    0.0848         0    0.1469    0.1859    0.1767    0.1854    0.1856    0.1648;
         0         0         0         0         0         0         0         0;
         0    0.0896    0.1619    0.1351         0         0         0         0;
         0         0         0         0         0         0         0         0];

Could you please help me on this.

[TADA]

KSSVs reahape seems the best solution for your problem, unless you are looking for some other output

[jaah navi]

but reshape makes use of reshaping from different column elements.

I want to reshape the elements present in its respective column.

For example

if

a= [4.7908    5.0104    5.1329    5.3186    5.3094    5.3070    5.4452     5.5001;
    0.0958    0.0994         0         0    0.1848    0.2020    0.1851    0.2146;
    0.0848         0    0.1469    0.1859    0.1767    0.1854    0.1856    0.1648;
         0         0         0         0         0         0         0         0;
         0    0.0896    0.1619    0.1351         0         0         0         0;
         0         0         0         0         0         0         0         0]

the the output shoud be

a= [4.7908         0         0    5.3186    5.3094    5.3070    5.4452    0;
    0         0.0994         0         0    0         0         0.1851    0.2146;
    0.0848         0    0.1469    0.1859    0         0.1854         0    0.1648;
    0.0958         0         0         0    0         0              0    5.5001;
    0         0.0896    0.1619         0    0.1848    0.2020         0    0;
    0         5.0104    5.1329    0.1351    0.1767         0    0.1856    0]

in the following random manner.