# is there any way to replace this code part with an equivalent part that runs faster?

2 views (last 30 days)
Mohamed Hassan on 21 May 2019
Answered: Walter Roberson on 21 May 2019
yy = 0.5*ones(300,500);
yy_abs = abs_coeff_mat.*yy;
yy_abs_cum=zeros(size(yy_abs));
for i = 2:size(yy_abs,1)
yy_abs_cum(i,:) = sum(yy_abs(1:i,:));
end

Jos (10584) on 21 May 2019
help cumsum

Walter Roberson on 21 May 2019
As you appear to be running those in a loop, move the
ones(300,500)
to outside the loop.
You do not appear to be doing implicit expansion, so size(yy_abs)appears to be the same as that 300, 500, so you can probably move the zeros(size(yy_abs)) to outside the loop too.
You can probably replace the loop with a cumsum() followed by zeroing the first row of the result.
I have to say that it looks odd that you would want row 2 to be the sum of row 1 and 2 of yy_abs, and row 3 to be the sum of rows 1, 2, 3 of yy_abs, and so on, but that you want row 1 of the output to be left at zero from the initialization to 0, instead of being the same as the first row of yy_abs.

R2018a

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