How to remove or identify spikes in a random signal.

17 views (last 30 days)
I have signal from different RFID tags. I just want to remove the spikes occurs in the signal.
Data file and signal images is attached. I have to remove the highlighted spikes.
Thanks. spikes.png
  4 Comments
Image Analyst
Image Analyst on 26 Apr 2019
"remove" means to clip/clamp/saturate, or to completely delete those elements from the array, essentially shortening it (it's less wide than before)?
Can you count on the spike always being below a threshold, and good values being above some threshold?
Subhash Sagar
Subhash Sagar on 26 Apr 2019
Thanks.
It can be any, either completely remove it or to saturate the values based on the previous trend. Both or either of them will work for me.
As its a real time data, we cannot set a threshold as in the current signal, outlier has lower as compared with previous value. But it is also possible that outlier value will be higher than the previous one.

Sign in to comment.

Accepted Answer

Akira Agata
Akira Agata on 26 Apr 2019
Looking at your data, negative spikes you mentioned is always less than 1000. So, if this condition is applicable to other data, you can simply remove them by:
idx = t1(:,3) < 1000;
t1(idx,:) = [];
If you have to detect negative peaks with more complex conditions, I believe findpeaks function will be some help.
  3 Comments
Akira Agata
Akira Agata on 26 Apr 2019
Thank you for your clarification.
Actually, rmoutlier might be one possible solution. But this function removes both higher- and lower-side outliers.
To remove lower-side outliers only, the following is one solution.
load('tag1.mat');
% Identify outliers of lower side
[~,lo] = isoutlier(double(t1(:,3)));
idx = t1(:,3) < int64(lo);
% Remove identified outliers
t1(idx,:) = [];

Sign in to comment.

More Answers (0)

Categories

Find more on Electrophysiology in Help Center and File Exchange

Products

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!