accumarray does not return the correct sum

2 views (last 30 days)
aggelos
aggelos on 13 Feb 2019
Commented: aggelos on 13 Feb 2019
Hello all,
I have a table dataset like below
table=
Date ID x y z Profit
'01-Jan-2019' 157350 0 1 100 0.470000000000000
'01-Jan-2019' 38715 0 1 100 1.05000000000000
'01-Jan-2019' 157350 0 1 100 0.540000000000000
'01-Jan-2019' 157350 0 1 100 0.320000000000000
'01-Jan-2019' 81074 1 1 100 2.28000000000000
'01-Jan-2019' 81074 1 1 100 1.66000000000000
'01-Jan-2019' 141788 0 1 100 0
'01-Jan-2019' 19105 0 1 300 -0.230000000000000
'01-Jan-2019' 19105 0 1 300 0.130000000000000
'01-Jan-2019' 5492 1 1 1500 7.51000000000000
'01-Jan-2019' 36435 0 1 100 0.110000000000000
'01-Jan-2019' 130445 1 1 100 -79.6700000000000
'01-Jan-2019' 130445 1 1 100 -78.4800000000000
'01-Jan-2019' 130445 1 1 100 -79.4300000000000
'01-Jan-2019' 154312 0 1 100 -2.39000000000000
'01-Jan-2019' 130445 1 1 100 -79.9200000000000
'01-Jan-2019' 130445 1 1 100 -80.7500000000000
'01-Jan-2019' 130445 1 1 100 -80.3100000000000
'01-Jan-2019' 130445 1 1 100 -80.0600000000000
'01-Jan-2019' 81074 1 1 100 1.62000000000000
I use
[ids, ~, rows] = unique(table(:, 2)); to get unique IDs and subscripts.
then I want to calculate the sum of positive profit and the sum of negative profit for each ID like:
myGrossprofit=accumarray(rows,table2array(table(:, 2)>0, @sum);
myGrossLoss=accumarray(rows, table2array(table(:, 2)<0, @sum);
But my results is not correct. It even shows an integer when Profit is decimal and my GrossLoss is a positive number.
Thanks in advance for any help.
  5 Comments
Walter Roberson
Walter Roberson on 13 Feb 2019
mask = YourTable{:,6}<0;
accumarray(rows(mask), YourTable{mask,6}, [max(rows),1],@sum)
aggelos
aggelos on 13 Feb 2019
Hi Walter,
It works like a charm using the mask. Thank you. I don't see an option to accept your answer thought?

Sign in to comment.

Answers (1)

Stephen23
Stephen23 on 13 Feb 2019
Edited: Stephen23 on 13 Feb 2019
Your data:
hdr = {'Date','ID','x','y','z','Profit'};
arr = {...
'01-Jan-2019' 157350 0 1 100 0.470000000000000
'01-Jan-2019' 38715 0 1 100 1.05000000000000
'01-Jan-2019' 157350 0 1 100 0.540000000000000
'01-Jan-2019' 157350 0 1 100 0.320000000000000
'01-Jan-2019' 81074 1 1 100 2.28000000000000
'01-Jan-2019' 81074 1 1 100 1.66000000000000
'01-Jan-2019' 141788 0 1 100 0
'01-Jan-2019' 19105 0 1 300 -0.230000000000000
'01-Jan-2019' 19105 0 1 300 0.130000000000000
'01-Jan-2019' 5492 1 1 1500 7.51000000000000
'01-Jan-2019' 36435 0 1 100 0.110000000000000
'01-Jan-2019' 130445 1 1 100 -79.6700000000000
'01-Jan-2019' 130445 1 1 100 -78.4800000000000
'01-Jan-2019' 130445 1 1 100 -79.4300000000000
'01-Jan-2019' 154312 0 1 100 -2.39000000000000
'01-Jan-2019' 130445 1 1 100 -79.9200000000000
'01-Jan-2019' 130445 1 1 100 -80.7500000000000
'01-Jan-2019' 130445 1 1 100 -80.3100000000000
'01-Jan-2019' 130445 1 1 100 -80.0600000000000
'01-Jan-2019' 81074 1 1 100 1.62000000000000
};
tbl = cell2table(arr,'VariableNames',hdr);
Code:
>> [G,ID] = findgroups(tbl.ID);
>> fun = @(v)[sum(v(v>0)),sum(v(v<0))];
>> Y = splitapply(fun,tbl.Profit,G);
>> [ID,Y]
ans =
5492 7.51 0
19105 0.13 -0.23
36435 0.11 0
38715 1.05 0
81074 5.56 0
130445 0 -558.62
141788 0 0
154312 0 -2.39
157350 1.33 0

Categories

Find more on Data Preprocessing in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!