Error while trying to code the Newton Method for a System of Equations

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Hi there. This is my first post in the forum. My name is Roberto and I am from Spain. Since English is not my home language, please do not be too hard to me, thanks.
Well, I coded the Newton Method for a System of Equations. It looks like:
function [x,fx,iters]=sistemanewton_sept(func,jacobi,x0,TOL,maxit)
%x0 vector
mitol=2*TOL; iters=1;
x0=x0(:); %Lo ponemos como vector columna
while (mitol>TOL && iters<maxit)
J=jacobi(x0); f=func(x0); en=-J\f; %¿sale vector columna directamente?
x=x0+en; x0=x;
if mitol>TOL
disp('ADVERTENCIA: No se pudo alcanzar la tolerancia deseada dentro del numero de iteraciones permitidas');
I don't know how to color the code. The error I get is:
??? Operands to the || and && operators must be convertible to logical scalar values.
Error in ==> sistemanewton_sept at 10
The functions I used in my code are: func and jacobi. They look like:
function f=func(x)
x1=x(1); x2=x(2);
f=[sqrt(x2*x2*x2/5), 0.25*(sin(x1)+cos(x2))]';
function J=jacobi(x)
x1=x(1); x2=x(2);
J=[0, sqrt(0.45*x2); 0.25*cos(x1), -0.25*sin(x2)];
That error is driving me crazy, since I never got it before. As I could read in some other post, that error is related to the way I use the "&&" operator, which must be only used to compare scalars. I am already comparing Scalars so...
Thank you so much.
  1 Comment
Star Strider
Star Strider on 13 Jul 2012
Edited: Star Strider on 13 Jul 2012
Your code looks good to me, but I may be missing something. To start troubleshooting, I suggest you put before your ‘while’ loop something like:
TestTol = mitol>TOL
TestItr = iters<maxit
TestClass = class([TestTol TestItr])
The variables ‘TestTol’ and ‘TestItr’ should both evaluate as ‘logical’. If they do not, then you have to find and correct the problem. If they are both ‘logical’ and you continue to get the error, I suggest adding parentheses to your ‘while’ statement:
while (mitol>TOL) && (iters<maxit)
while ((mitol>TOL) && (iters<maxit))
Since ‘func’ and ‘jacobi’ do not use the logical operators, they are probably not the problem.

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Answers (1)

Kye Taylor
Kye Taylor on 13 Jul 2012
The first time you enter the while loop, you are comparing scalars (assuming the input TOL is a scalar). However, when you overwrite mitol with the absolute value of the output from func, mitol becomes nonscalar since func outputs a 2-by-1 vector.
  1 Comment
Roberto on 13 Jul 2012
Edited: Roberto on 13 Jul 2012
Oh... you are right, I forgot f(x0) was a vector... I replaced that line with this new one: mitol=norm(func(x0));
Thank you Kye Taylor, very helpful.

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