plotting matrix verses vector
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Good evening
I want to plot a frequency vector (x-axes) with a path loss matrix which is 16*16
I tried this but it gives me an error
figure(1);
plot(p.f,H(1,:),
p.f,H(2,:),
p.f,H(3,:),
p.f,H(4,:),
p.f,H(5,:),
p.f,H(6,:),
p.f,H(7,:),
p.f,H(8,:),
p.f,H(9,:),
p.f,H(10,:),
p.f,H(11,:),
p.f,H(12,:),
p.f,H(13,:),
p.f,H(14,:),
p.f,H(15,:),
p.f,H(16,:));
Answers (2)
Star Strider
on 26 Oct 2018
The easiest solution is likely:
plot(p.f, H)
If ‘H’ is a square matrix, and you want to transpose it, use:
plot(p.f, H.')
instead.
2 Comments
Star Strider
on 26 Oct 2018
I assumed ‘p.f’ is a vector.
If it a matrix the same size as ‘H’, either of my plot calls will work:
p.f = rand(16);
H = rand(16, 16);
figure
plot(p.f, H)
If not, you will have to choose what vector in ‘p.f’ to plot with. The vector must have 16 elements to plot with your (16x16) matrix.
madhan ravi
on 26 Oct 2018
Edited: madhan ravi
on 26 Oct 2018
An example its possible using loop:
H=rand(16)
p.f = 1:16
figure(1);
for i = 1:length(H)
plot(p.f(1,:),H(i,:))
hold on
end
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