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Formatting data using an if function

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Hello everybody, how can I adjust the data, so that the purple curve will always be connected? The next purple section should start at the end of the section before.... I've no clue how to do that. I really need help, because of this thing I'm not able to finish my bachelor thesis. Thanks guys.
(Ignore the legend)
C=cumsum(diffE,'omitnan'); % needed Capacity
Cbmax= 1000; % in MWH, max. capacity of the battery storage
Cbmin= 100; % in MWh, deep charge border
imax= C>=Cbmax-Cbmin; % find where C is larger than the Capacity
imin= C<=0; % find where C is =0
C(imax) = Cbmax-Cbmin; % if C is larger than Cbmax: C=Cbmax
C(imin) = Cbmin-Cbmin; % if C is smaller than Cbmin: C=Cbmin
Cres=cumsum(diffE,'omitnan');
for k=1:length(Cres)-1
if Cres(k)>(Cbmax-Cbmin) && Cres(k)>Cres(k+1)
C(k+1)=C(k)-Cres(k)+Cres(k+1);
end
if Cres(k)>(Cbmax-Cbmin) && C(k)<(Cbmax-Cbmin)
C(k+1)=C(k)-Cres(k)+Cres(k+1);
end
end

Accepted Answer

Stephen23
Stephen23 on 21 Sep 2018
Edited: Stephen23 on 22 Sep 2018
"how can I adjust the data, so that the purple curve will always be connected?"
  • loop over the length of the data vector.
  • detect any discontinuities (e.g. difference/offset, or some other metric).
  • shift the remaining data by the detected offset (use indexing).
Something like this:
for k = 2:numel(vec)
d = diff(vec(k-1:k))
if abs(d)>tol % pick a tolerance, or some metric
vec(k:end) = vec(k:end)-d;
end
end
I just tried this on a fake data vector:
tol = 2;
vec = [0,1,2,3,4,10,11,12,13];
giving:
>> vec
vec =
0 1 2 3 4 4 5 6 7
You could fine-tune the algorithm so that it includes an offset of the same sign as d, but with magnitude tol. Also it would pay to do some reading into detecting discontinuities:
  3 Comments
Stephen23
Stephen23 on 22 Sep 2018
Edited: Stephen23 on 22 Sep 2018
"But unfortunately the diff functions is always in an endless loop"
Check if you have any other functions named diff:
which diff -all
And if so, rename them. Also ensure that you do not have any variables name diff. Note that diff is not strictly required, you could do this:
d = vec(k)-vec(k-1)
Benedikt Wessel
Benedikt Wessel on 22 Sep 2018
Oh nice, now it's working. I although tried to use indexing to find the gaps and to adjust them, but my code is a mess I think. Sorry to bother you, but can you find my mistakes? I also added the needed data if it's helpful. Here's my code:
C=cumsum(diffE,'omitnan'); % needed Capacity, will be adjusted by Cbmax anc Cbmin
Cres=C;
Cbmax= 1000; % in MWH, max. capacity of the battery storage
Cbmin= 100; % in MWh, deep charge border
imax= C>=Cbmax-Cbmin; % find where C is larger than the Capacity
imin= C<=0; % find where C is =0
C(imax) = Cbmax-Cbmin; % if C is larger than Cbmax: C=Cbmax
C(imin) = Cbmin-Cbmin; % if C is smaller than Cbmin: C=Cbmin
Cres=cumsum(diffE,'omitnan');
change=zeros(length(diffE),1);
for k=1:length(Cres)-1
if Cres(k)>(Cbmax-Cbmin) && Cres(k)>Cres(k+1)
C(k+1)=C(k)-Cres(k)+Cres(k+1);
end
if Cres(k)>(Cbmax-Cbmin) && C(k)<(Cbmax-Cbmin)
C(k+1)=C(k)-Cres(k)+Cres(k+1);
end
change(k)= Cres(k)>(Cbmax-Cbmin) && Cres(k+1)<(Cbmax-Cbmin);
end
cha=find(change==1); % find the positions of the gaps between the sections
for k = 1:length(C)-1
for n=cha
if C(k)==C(n) % find the data with the "crack"
C(k:n+1) = C(k:n+1)-C(n)-C(n-1); % subtract every value in the actual section with the difference between the sections
end
end
end

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More Answers (1)

Walter Roberson
Walter Roberson on 21 Sep 2018
  1 Comment
Benedikt Wessel
Benedikt Wessel on 21 Sep 2018
Thanks. But I don't need to interpolate the values. I need all values to be lower to fit the section before.

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