Changing block row matrix to block column matrix?

I have a block matrix p = [A B C ...]. I want to change the matrix into a column block matrix without changing the elements of inner matrices (A, B, ...).

[madhan ravi]

An example?

[Seyyed Mohammad Saeed Damadi]

A = [1 2; 3 4];
B = [1 1; 1 1];
C = [3 3; 4 4];
P = [A B C];

I want

Q = [1 2 ;1 1 ;3 3; 3 4 ;1 1 ;4 4];

How can I do it using matrix multiplication or any other functions?

[Walter Roberson]

Q = P;

P is already what you list as your desired output.

[Seyyed Mohammad Saeed Damadi]

Sorry, I had made a mistake.

Answer 1

[Andrei Bobrov]

[EDIT]

B = 2; % the number of blocks 
[m,n] = size(c);
out = reshape(permute(reshape(c,m,n/B,[]),[1,3,2]),m*B,[]);

[Seyyed Mohammad Saeed Damadi]

The fist one does not work for my case. The reason is as follows:

a = [0.8166    0.8330    0.4215;0.1817    0.4063    0.5333];

b = [0.4303    0.6647    0.5919;0.0024    0.2568    0.3578];

c = [a b];

c = [0.8166    0.8330    0.4215    0.4303    0.6647    0.5919;0.1817    0.4063    0.5333    0.0024    0.2568    0.3578];

So using Q = reshape(c.',2,[])'

Gives

Q = [0.8166    0.8330    0.4215;0.4303    0.6647    0.5919;0.1817    0.4063    0.5333;0.0024    0.2568    0.3578];

as you can see the second row of a has been swapped by the first row of b. I want a and b at one column.

My original problem is as follow:

I have a row block matrix, I know the number of blocks which is N. Hence, c = [a1 a2 a3 a4 ...]. All ai's have the same shape. Without changing the elements of ai's, I want to order them as a column block matrix?

As an example, we can have ai = rand(2,3) i=1:4 b = [a1 a2 a3 a4]. How we can have a block column matrix?

[Walter Roberson]

Q = reshape(c.',size(c,2),[])'

perhaps

[Andrei Bobrov]

Please see my answer after edit.

[Seyyed Mohammad Saeed Damadi]

It works. Thank you.