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Please help me convert equation to matlab code.
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Deal all.
I need you help to convert this equation to matlab code
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/171729/image.jpeg)
I spend a lot of time to write it but it doesn't work. Thank you.
1 Comment
Walter Roberson
on 1 Apr 2018
Are you permitted to use the symbolic toolbox?
Is the question about providing some kind of symbolic proof, or is it about calculation of the formula using finite precision and a particular numeric input?
Answers (8)
Roger Stafford
on 1 Apr 2018
N = 100; % <-- Choose some large number
s = x;
for n = 2*N-1:-2:1
s = x - s*x^2/((n+2)*(n+1));
end
(I think you meant to take the limit as N approaches infinity, not x.)
0 Comments
kalai selvi
on 15 Sep 2020
pls answer this question ...how to write the equation into code
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/360760/image.png)
2 Comments
Walter Roberson
on 15 Sep 2020
π is written as pi in MATLAB.
exp of an expression is written as exp(expression) in MATLAB.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/360979/image.png)
kalai selvi
on 16 Sep 2020
How to write a code on IOTA filter in fbmc system
2 Comments
Walter Roberson
on 16 Sep 2020
Edited: Walter Roberson
on 17 Sep 2020
Warning: pudn has questionable security. Take precautions when you access it.
Kunwar Pal Singh
on 26 Apr 2021
please answer this....how to write this equation into MATLAB CODE
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/596770/image.jpeg)
1 Comment
Walter Roberson
on 26 Apr 2021
%these variables must be defined in a way appropriate for your situation
S_N = rand() * 10
theta = randn() * 2 * pi
l = randi([2 10])
b_1 = rand()
c_11 = rand()
t_year = randi([1950 2049])
d_11 = rand()
t_1 = rand()
t_x = t_1 + rand()
lambda_a = randi([500 579])
LOTF_a = rand()
P = rand()
K_l = rand()
k_0 = rand()
t_tau = randi(10)
overhaulcost_a = 1000 + rand()*100
%the work
syms t
part1 = int(S_N .* cos(theta) .* l .* b_1 .* t_year .* d_11, t, t_1, t_x);
part2 = int(lambda_a .* LOTF_a, t, t_1, t_x);
part3 = int(P*K_l .* t_year + P .* k_0 .* l .* l .* t_tau, t, t_1, t_x);
part4 = overhaulcost_a ;
result = part1 - part2 - part3 - part4;
Jakub Laznovsky
on 19 May 2021
Hi guys, can you please help me with conversion this piece of code to the mathematical equation?
It i a simple 3D mask proceeding the image, and searching for adjoining number one and number two. Thank you in advance.
Code:
m1=[0 0 0; 0 1 0; 0 0 0];
m2=[0 1 0; 1 1 1; 0 1 0];
mask=zeros(3,3,3);
mask(:,:,1)=m1;mask(:,:,2)=m2;mask(:,:,3)=m1;
for i=2:size(image,1)-1
for j=2:size(image,2)-1
for k=2:size(image,3)-1
help_var=image(i-1:i+1,j-1:j+1,k-1:k+1);
if sum(unique(help_var(mask==1)))==3
new_image(i,j,k)=3; %marks adjoining pixel with number 3
end
end
end
end
4 Comments
Adhin Abhi
on 4 Jan 2022
(λlog vmax−log vmin) /(vmax−vmin )
1 Comment
Walter Roberson
on 4 Jan 2022
(lambda .* log(vmax) - log(vmin)) ./ (vmax - vmin)
Lukasz Sarnacki
on 17 Aug 2022
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1100455/image.png)
Please help
5 Comments
Lukasz Sarnacki
on 17 Aug 2022
Thay all are arrays
A(x; y) is the average intensity of the fringe image
B(x; y) is the so-called intensity modulation.
ϕ is the corresponding wrapped phase
Walter Roberson
on 18 Aug 2022
syms n N integer
syms A(x,y) B(x,y) phi(x,y)
Pi = sym(pi)
I(n,x,y) = A(x, y) + B(x,y) * cos(phi(x,y) - 2*Pi*n/N)
numerator = simplify(symsum(I(n, x, y) .* sin(2*Pi*n/N), n, 0, N-1))
denominator = simplify(symsum(I(n, x, y) .* cos(2*Pi*n/N), n, 0, N-1))
eqn = phi(x,y) == atan(numerator ./ denominator)
simplify(eqn)
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