How can I find the location of a substring in a char array

I am trying to find the location of a substring in a char array

I have the variable comtext=7143x53 char each line is a string e.g.

HRV: Beat 1 : First beat in block

HRV: Beat 2; Interval 1 = 1034.93 ms (Normal)

HRV: Beat 3; Interval 2 = 1037.54 ms (Normal)

HRV: Beat 4; Interval 3 = 1007.84 ms (Normal)

HRV: Beat 5; Interval 4 = 972.177 ms (Normal)

HRV: Beat 6; Interval 5 = 970.848 ms (Normal)

start EO

HRV: Beat 7; Interval 6 = 945.21 ms (Normal)

HRV: Beat 8; Interval 7 = 962.898 ms (Normal)

I am trying to find the row number containing a particular beat (not all rows contain beats)

attempts so far include

>> idx = all(contains(comtext,'Beat 2'),2)
Undefined function 'contains' for input arguments of type
'char'.

   k=strfind(comtext, 'Beat 2;')
  Error using strfind
  Input strings must have one row.

idx = all(ismember(comtext,'Beat 2'),2)

fails because I do not know in advance the entire text of the string containing the relevant beat, just the substring containing the beat number

any advice for finding the row whose string contains the relevant substring would be much appreciated

I am new to matlab, and am beginning to consider copying the relevant variables to excel to work with and then back to matlab for processing, but there must be a better solution

Thanks,

Jonathan

[Walter Roberson]

I predict you are using a version earlier than R2016b, but you will need to tell us which version you are using.

[Jonathan]

Apologies, I am using 2013b

Answer 1

[Stephen23]

C = [...
'HRV: Beat 1 : First beat in block            '
'HRV: Beat 2; Interval 1 = 1034.93 ms (Normal)'
'HRV: Beat 3; Interval 2 = 1037.54 ms (Normal)'
'HRV: Beat 4; Interval 3 = 1007.84 ms (Normal)'
'HRV: Beat 5; Interval 4 = 972.177 ms (Normal)'
'HRV: Beat 6; Interval 5 = 970.848 ms (Normal)'
'start EO                                     '
'HRV: Beat 7; Interval 6 = 945.21 ms (Normal) '
'HRV: Beat 8; Interval 7 = 962.898 ms (Normal '
];

>> X = ~cellfun('isempty',strfind(cellstr(C),'Beat 2'))
X =
  0
  1
  0
  0
  0
  0
  0
  0
  0
>> find(X) % to get row number.
ans =  2

[Jonathan]

Thank you very much, works beautifully