How to work out the position vector?
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The position vector a=[20sint;20cost;0] varies with time from t=0 to t=40 at 0.4 intervals. How do I calculate the values of a? I keep getting the message error using vertcat
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Answers (1)
M
on 31 Oct 2017
If you define
t=0:0.4:40;
then you have
size(sin(t))
ans =
1 101
but 0 is a scalar of dimension 1*1
You should use
zeros(1,101);
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