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How to Assign Values from a Struct to a Matrix in a For Loop?

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A.B.C = [1 2 3];
A.B.D = [3 4 5];
for k = 1:2
G(k, :) = A.B.C;
G(k, :) = A.B.D;
end
G
G returns:
3 4 5
3 4 5
Why doesn’t it return the following? What is the solution to have a G like the following?
1 2 3
3 4 5

Answers (1)

Walter Roberson
Walter Roberson on 4 Mar 2017
G(1,:) = A.B.C;
G(2,:) = A.B.D;
No loop.
  2 Comments
Rightia Rollmann
Rightia Rollmann on 4 Mar 2017
Edited: Rightia Rollmann on 4 Mar 2017
What if instead of two fields, I had 50 fields?
Isn't there any way to use a for loop to dynamically make a matrix out of vectors stored in a struct?

This question is closed.

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