minimum of an array

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Rakshmy C S on 10 Dec 2011
Hi, I have a 10*10 array.I need to find the minium of all the rows of the array except selected ones.For eg. to find the minimum of the array except 2nd and fifthrow.

Andrei Bobrov on 13 Dec 2011
r = [1 3 5];
A1 = A;
A1(r,:) = nan;
[c,idx] = min(A1(:));
[i1,j1] = ind2sub(size(A1),idx);
Rakshmy C S on 13 Dec 2011
thanks a lot.its working.

Sean de Wolski on 12 Dec 2011
A = [999, 25.019, 1.414, 25.806, 1.414, 3.316, 4.472, 29.782, 26.248, 28.248
25.019, 999, 25.059, 5.291, 25.495, 25.278, 25.573, 8.774, 3.316, 7.348
1.414, 25.059, 999, 25.612, 2.449, 4.358, 5.477, 29.546, 26.134, 28.035
25.806, 5.291, 25.612, 999, 26.495, 26.514, 27.092, 5.385, 4.795, 8.124
1.414, 25.495, 2.449, 26.495, 999, 2.236, 3.162, 30.577, 26.739, 28.635
3.316, 25.278, 4.358, 26.514, 2.236, 999, 1.732, 30.822, 26.645, 28.513
4.472, 25.573, 5.477, 27.092, 3.162, 1.732, 999, 31.416, 26.925, 28.670
29.782, 8.774, 29.546, 0, 30.577, 30.822, 31.416, 999, 7.874, 10.535
26.248, 3.316, 26.134, 4.795, 26.739, 26.645, 26.925, 7.874, 999, 4.358
28.248, 7.348, 28.035, 8.124, 28.635, 28.513, 28.670, 10.535, 4.358, 999];
exc = [1 3 5];
[Amin idc] = min(A(setdiff(1:size(A,1), exc),:),[],2);
[Amin idr] = min(Amin);
idc = idc(idr);
idr = idr+sum(exc<=idr);
fprintf('Minimum %f at row %i col %i\n',Amin,idr,idc);
Minimum 0.000000 at row 8 col 4
I added a zero to test it.
Rakshmy C S on 13 Dec 2011
Thank you. this code is also working

Walter Roberson on 10 Dec 2011
Create a new matrix that includes only the desired information, and apply the minimum to that.
This can possibly be done without any assignment to variables, by using indexing, but whether you will be able to handle things that way depends on your intention.
B = A; %work on a copy, not the original
B([2 5],:) = []; %remove the 2nd and 5th rows
%now apply the appropriate min() function to B.
or
apply min() to A(setdiff(1:size(A,1), [2 5]),:)
I am being vague about the min because I cannot tell whether you mean minimum across each row with rows 2 and 5 happening not to be wanted; or if you minimum down each column after row 2 and 5 have been ignored; or if you want the minimum over the entire array but excluding the content of rows 2 and 5.
Walter Roberson on 10 Dec 2011
min(min(A(setdiff(1:size(A,1), [2 5]),:)))

Mohsen Davarynejad on 10 Dec 2011
My guess is the the following scales better:
B = A; %work on a copy, not the original
B([2 5],:) = []; %remove the 2nd and 5th rows
[Min, MinIndex] = min(B(:));
Walter Roberson on 12 Dec 2011
I see what you mean, and I have an idea of how to correct for it, but I need to work on other things now.