I'm trying to integrate using Simpson's rule
3 views (last 30 days)
Show older comments
I'm trying to integrate sin(x) from 0 to pi using the simpson's rule. The only thing is I need it to output several iterations each with a different number of intervals. For example, n= 4, 8 , 16, 32, 64. Here is my code so far clear; close all; clc;
ezplot('sin(x)', [0, pi]), hold on
f=@(x) sin(x);
a=0;b=pi;
n=4;
h=(b-a)/n;
p=0;
for i=a:b
p=p+1;
x(p)=i;
y(p)= sin(i);
plot(x, sin(x), 'r')
end
l=length(x);
x
y
any help appreciated!
0 Comments
Answers (1)
Walter Roberson
on 13 May 2015
So instead of "n=4" use
for n = [4, 8, 16, 32, 64]
and put an "end" after.
2 Comments
Walter Roberson
on 14 May 2015
for n = [4, 8, 16, 32, 64]
h=(b-a)/n;
p=0;
for i=a:b
p=p+1;
x(p)=i;
y(p)= sin(i);
plot(x, sin(x), 'r')
drawnow();
end
l=length(x);
x
y
end
Right at the end.
Note that I also added a drawnow() call so you have a hope of seeing the plots you are generating. I have no idea why you would want to plot in the manner you are plotting, but I guess you must have a reason.
See Also
Categories
Find more on Numerical Integration and Differential Equations in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!