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Sorting array of sym

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Tanmaya
Tanmaya on 15 Jul 2024
Commented: Tanmaya on 18 Jul 2024
I get wrong answers in this case. Am I doing anything wrong ?
>> a = sym.empty();
>> a = [a,0,pi,pi/2,-pi/2,pi/4]
a =
[0, pi, pi/2, -pi/2, pi/4]
>> sort(a)
ans =
[0, pi, -pi/2, pi/2, pi/4]
  4 Comments
Walter Roberson
Walter Roberson on 15 Jul 2024
Pi = sym(pi);
a = [-Pi/4 -Pi/3 -Pi/2 -Pi -Pi*3/4 -Pi*2/3 Pi/4 Pi/3 Pi/2 Pi Pi*3/4 Pi*2/3 -Pi*1/5 -Pi*2/5 -Pi*3/5 -Pi*4/5 Pi*1/5 Pi*2/5 Pi*3/5 Pi*4/5]
a = 
sort(a)
ans = 
a = a(randperm(numel(a)))
a = 
sort(a)
ans = 
So the sorting results are stable, but they are not obvious.
Tanmaya
Tanmaya on 18 Jul 2024
Thanks

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Answers (1)

Milan Bansal
Milan Bansal on 15 Jul 2024
Hi Tanmaya
To sort the symbolic array numerically, you can convert the symbolic expressions to their numerical equivalents before sorting. Here's how you can do it:
  1. Convert the symbolic expressions to numerical values.
  2. Sort the numerical values.
  3. Recreate the sorted symbolic array using the indices from the sorted numerical values.
Please refer to the following code snippet to implement the same:
a = sym.empty();
a = [a, 0, pi, pi/2, -pi/2, pi/4];
a = sym(a); % Ensure the array is symbolic
% Convert to numerical values
num_a = double(a);
% Sort the numerical values and get the sorting indices
[sorted_num_a, sort_idx] = sort(num_a);
% Recreate the sorted symbolic array using the indices
sorted_a = a(sort_idx);
disp(sorted_a);
Hope this helps!
  2 Comments
John D'Errico
John D'Errico on 15 Jul 2024
This is pretty much all you can do, to convert the elements to actual numbers in some form. But there is no value in creating a as a sym.empty first.
a = sym([0, pi, pi/2, -pi/2, pi/4]);
a = sym(a)
a = 
You don't need ot go all the way to doubles though. vpa would seem more accurate, and still works.
[~,idx] = sort(vpa(a));
a = a(idx)
a = 
Tanmaya
Tanmaya on 18 Jul 2024
Thanks

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