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I keep getting the error message that the variables must be of data type double and it is currently of type sym.

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%I'm unsure how else to run this code to solve the 10 eqn system where
%the answer comes out in the correct form, please help
syms AB BC AD BD CD DE CE Ax Ay Ey
eqn1=Ax+AD==0;
eqn2=Ay+AB==0;
eqn3=74+BC+(3/5)*BD==0;
eqn4=-AB-(4/5)*BD==0;
eqn5=-BC+(3/5)*CE==0;
eqn6=-24-CD-(4/5)*CE==0;
eqn7=-AD+DE-(3/5)*BD==0;
eqn8=CD+(4/5)*BD==0;
eqn9=-DE-(3/5)*CE==0;
eqn10=Ey+(4/5)*CE==0;
[AB BC AD BD CD DE CE Ax Ay Ey]=solve(eqn1, eqn2, eqn3, eqn4, eqn5, eqn6, eqn7, eqn8, eqn9, eqn10,[AB BC AD BD CD DE CE Ax Ay Ey])
AB = 
BC = 
AD = 
74
BD = 
CD = 
DE = 
46
CE = 
Ax = 
Ay = 
Ey = 
  2 Comments
Ana
Ana on 21 Feb 2024
it is still giving me these error messages
"Variable AB must be of data type double. It is currently of type sym. Check where the variable is assigned a value."
is it because I introduce them using 'syms', it also said i cannot use rehash in my code on Matlab Grader

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Accepted Answer

Walter Roberson
Walter Roberson on 21 Feb 2024
%I'm unsure how else to run this code to solve the 10 eqn system where
%the answer comes out in the correct form, please help
syms AB BC AD BD CD DE CE Ax Ay Ey
eqn1=Ax+AD==0;
eqn2=Ay+AB==0;
eqn3=74+BC+(3/5)*BD==0;
eqn4=-AB-(4/5)*BD==0;
eqn5=-BC+(3/5)*CE==0;
eqn6=-24-CD-(4/5)*CE==0;
eqn7=-AD+DE-(3/5)*BD==0;
eqn8=CD+(4/5)*BD==0;
eqn9=-DE-(3/5)*CE==0;
eqn10=Ey+(4/5)*CE==0;
[AB BC AD BD CD DE CE Ax Ay Ey]=solve(eqn1, eqn2, eqn3, eqn4, eqn5, eqn6, eqn7, eqn8, eqn9, eqn10,[AB BC AD BD CD DE CE Ax Ay Ey]);
AB = double(AB);
BC = double(BC);
AD = double(AD);
BD = double(BD);
DE = double(DE);
CE = double(CE);
Ax = double(Ax);
Ay = double(Ay);
Ey = double(Ey);

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