ploting Mitagg leffler function

Hello h
How can I plote the Mittage leffler for the function in [0,50], Here is the code but I do not know how to define the function.
I appreciate your help.
alpha=0.5;
beta=1.2;
function E= ML(z,alpha,beta)
plot(E)
end

Answers (3)

Follow this approach. Let's say you'd need to plot: f(a, b, t) = a*exp(cos(b*t)) using a nested function.
a = 2.13;
b = 3.5;
t = linspace(-10, 10, 500);
OUTPUT=My_Fun(a, b, t);
function F = My_Fun(a, b, t)
F = a*exp(cos(b*t));
plot(t, F)
end

5 Comments

Thank you for help. But in the follwing code there is an error (Unrecognized function or variable 'E') , and I do not know how to fix it
alpha=0.2;
beta=0.3;
t = linspace(0, 1, 50);
z=-sqrt(t);
function E= ML(z,alpha,beta)
plot(E,t)
end
Yes, MATLAB's question is justified: You say you want to return "E" from your function "ML":
function E= ML(z,alpha,beta)
but you don't define it therein. You only write a senseless plot command:
plot(E,t)
What Torsten indicated is that you should define what is the formulation of E.
eg.,: E = alpha+beta*z
E is sum_{k=0}^{infty} z^k/Gamma(alpha*k+beta) and I wrote it as
syms k z alpha beta
E=symsum(z^k/gamma(alpha*k+beta),k,0,Inf)
but still not working
alpha = sym(0.5);
beta = sym(1.2);
syms k z
E(z) = symsum(z^k/gamma(alpha*k+beta),k,0,Inf)
E(z) = 
t = linspace(-10, 10, 50).';
Y = E(sqrt(sym(t)))
Y = 
y = double(Y);
subplot(2,1,1); plot(t, real(y), 'k-.'); title('real part');
subplot(2,1,2); plot(t, imag(y), 'r:.'); title('imag part')

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As shown in one of the matlab exchange, edit this below shown function file using your own input variables, viz. k, z, alpha, beta
a = ?;
b = ?;
c = ?;
x = ?;
OUTPUT=ML_fun(a, b, c, x);
function f=ML_fun(a,b,c,x)
gamma_c=1.0/gamma(c);
f=0; fa=1; j=0;
while norm(fa,1)>=eps
fa=(gamma(c+j)*gamma_c)/gamma(j+1)/gamma(a*j+b) *x.^j;
f=f+fa; j=j+1;
% You can also add: plot(), hold on % see the simulation progress of ML
% fcn
end
% Or here: plot()
end

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Erm
on 10 Sep 2023

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