Function inside a for loop
2 views (last 30 days)
Show older comments
Hi,
I have a function that works well when I called it one by one.
>>Calculate(a,cs,sclk)
ans: 20
>>Calculate(a,cs,sclk)
ans: 20.5
>>Calculate(a,cs,sclk)
ans: 20.25
However, when i switching the function inside a for loop, it kept produced the same answer.
for j=1:9
d=Calculate(a,cs,sclk);
fprintf('value %d is %d\n',j,d);
end
Asnwer:
value 1 is 10
value 2 is 10
.
.
.
value 9 is 10
And I called it in a series. They all produced the same answer.
>> d1=Calculate(a,cs,sclk);d2=Calculate(a,cs,sclk);d3=Calculate(a,cs,sclk);d4=Calculate(a,cs,sclk);
Ans:d1=15,d2=15,d3=15,d4=15,d5=15
Anyone know what's happened for my function here?
4 Comments
Askic V
on 17 Dec 2022
You can measure time with tic and toc.
Please have a look at:
https://www.mathworks.com/help/matlab/ref/tic.html
Accepted Answer
Askic V
on 17 Dec 2022
Moved: Walter Roberson
on 18 Dec 2022
For loop will be executed in a matter of milliseconds. On the other hand when you call function once at a time, there is a significantly more time difference between calls. So perhaps your input parameters cannot change fast enough in the loop call.
2 Comments
More Answers (0)
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!