Calculating Value of Inverse function

Hi
I have the function f(x) = x^2/(1+sqrt(x)) and I am trying to calulate the value of the invrese function at 2 i.e. F^-1(2)
I am trying to use 'finverse' but and have succefulle extracted the inverse function and seperatley calculating the value but nor during the same attempt.
this is the latest attempt
sym x
x = 2;
g = finverse(x.^2./(1+sqrt(x)),x);
f = @(x) g;
disp(f(2))

 Accepted Answer

syms x
g = finverse(x.^2./(1+sqrt(x)),x);
% x = 2;
f = @(x) g;
disp(f(2))

1 Comment

syms x
g = finverse(x.^2./(1+sqrt(x)),x);
% x = 2;
f = @(x) g;
double(subs(g,x,2))
ans = 2.2336

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More Answers (1)

How about this?
syms x
f(x) = (x^2)/(1 + sqrt(x));
g = finverse(f)
g(x) = 
double(g(2))
ans = 2.2336

6 Comments

You are getting the answer I am looking for but for some reason I am getting the following error
Error using sym/subsindex
Invalid indexing or function definition. Indexing must follow MATLAB
indexing. Function arguments must be symbolic variables, and function
body must be sym expression.
Error in A_3_1_31 (line 3)
f(x) = (x^2)/(1 + sqrt(x));
It thinks you used symbolic variable "x" as indices
syms x
x = 2; % <--- because of this line
f(x) = (x^2)/(1 + sqrt(x));
g = finverse(f)
You can comment out it.
Copied your code directly and got that error
clear
check the workspace variables if it has x value assigned to 2, use clear and try again
Hmm... This is strange. No error on mine.
Perhaps try clearing the variables from your Workspace. Then test the code again.
Have you tried @VBBV's code on your MATLAB?
Clearing the workspace worked, my bad.

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R2022a

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Asked:

on 17 Oct 2022

Commented:

on 17 Oct 2022

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