A compact way to remove empty rows in a cell array matrix ?

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A compact way to remove empty rows in a cell array matrix, as the following one?
>> a
a =
8×2 cell array
{'22-Jul-2021 17:00:00'} {[ 49]}
{0×0 double } {0×0 double}
{0×0 double } {0×0 double}
{0×0 double } {0×0 double}
{0×0 double } {0×0 double}
{'27-Jul-2021 20:00:00'} {[ 123]}
{'28-Jul-2021 06:00:00'} {[ 21]}
{'29-Jul-2021 13:00:00'} {[ 66]}
I tried this solution, but is there any more compact way ?
i = cellfun(@isempty,a);
a( any(i,2), : ) = []
a =
4×2 cell array
{'22-Jul-2021 17:00:00'} {[ 49]}
{'27-Jul-2021 20:00:00'} {[123]}
{'28-Jul-2021 06:00:00'} {[ 21]}
{'29-Jul-2021 13:00:00'} {[ 66]}
  4 Comments

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Accepted Answer

Matt J
Matt J on 11 Aug 2022
a = {
'22-Jul-2021 17:00:00', 49
'', []
'', []
'', []
'', []
'27-Jul-2021 20:00:00', 123
'28-Jul-2021 06:00:00', 21
'29-Jul-2021 13:00:00', 66 }
a = 8×2 cell array
{'22-Jul-2021 17:00:00'} {[ 49]} {0×0 char } {0×0 double} {0×0 char } {0×0 double} {0×0 char } {0×0 double} {0×0 char } {0×0 double} {'27-Jul-2021 20:00:00'} {[ 123]} {'28-Jul-2021 06:00:00'} {[ 21]} {'29-Jul-2021 13:00:00'} {[ 66]}
a= table2cell(rmmissing(cell2table(a)))
a = 4×2 cell array
{'22-Jul-2021 17:00:00'} {[ 49]} {'27-Jul-2021 20:00:00'} {[123]} {'28-Jul-2021 06:00:00'} {[ 21]} {'29-Jul-2021 13:00:00'} {[ 66]}
  3 Comments
Sim
Sim on 11 Aug 2022
Edited: Sim on 11 Aug 2022
@Matt J, cool, thanks a lot!
@Stephen23, many thasnks :-)

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