How do I find sin of a cell variable (el)?

Assuming el is cell variable with a matrix of 30 X 3300 being rows and colums.

for PRN =1:30
    for t = 1:3300
        M_d(PRN,t)= 1/(sin(el(PRN,t))+(0.00143/tan(el(PRN, t))+0.0445));
        M_w(PRN, t)=1/(sin(el)+(0.00035/tan(el)+0.017));
    end
end

The error i had.

Check for incorrect argument data type or missing argument in call to function 'sin'.

[Stephen23]

You used the wrong type of indexing. Indexing cell arrays is very simple:

• () parentheses refers to the cells themselves.
• {} curly braces refers to the cell content.

If you want to refer to the cell content, then you need to use curly braces.

See: https://www.mathworks.com/help/matlab/matlab_prog/access-data-in-a-cell-array.html

[Tunde Adubi]

I have done so, but I keep getting an undefined error whic is quite unrelated with the other.

Thanks anyway

for t = 1:3316
        M_d(PRN,t)= 1/sin{el{PRN,t}} + (0.00143/tan{el{PRN, t}}+0.0445);
        M_w(PRN,t)=1/(sin{el{PRN,t}}+(0.00035/tan{el{PRN, t}}+0.017));
    end

Undefined variable sin.

Error in Troposphere (line 29)

M_d(PRN,t)= 1/sin{el{PRN,t}} + (0.00143/tan{el{PRN, t}}+0.0445);

[Stephen23]

SIN is a function. Functions in MATLAB are always called using parentheses, not curly braces like you used.

M_d(PRN,t)= 1/sin{el{PRN,t}} + (0.00143/tan{el{PRN, t}}+0.0445);
%                ^         ^               ^          ^  should be parentheses

[Tunde Adubi]

Oh, it worked. Thanks for pointing that out.

[Walter Roberson]

Could you confirm that each entry in the cell is a numeric scalar? Your code will fail otherwise.

If it is a numeric scalar then use cell2mat and simple vectorized numeric calculations. Remember to switch from / to ./

Answer 1

[Davide Masiello]

If the value is stores in a cell, then you should write

el{PRN,t} 

in order to extract the value as a double.