Area under a peak

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Haris Ashraf
Haris Ashraf on 11 Apr 2022
Commented: Mathieu NOE on 11 Apr 2022
Hi, I am struggling with calculating the area under the peak shown in the graph by red color. I want to calculate the area under the peak as well as area of the entire curve (including the peak).
The data file in.txt format has x and y axis data.

Answers (2)

Mathieu NOE
Mathieu NOE on 11 Apr 2022
hello
based on @Davide Masiello excellent proposition, I tried to make the selection of the peak zone a bit more automatic...
the computation of the area of the peak may significantly vary based on where start and stop the selected segment , as how much of the root (being wider) will impact the result
this is how is works with the code below :
you can change the threshold (threshold_above_curve) to see the effect
clear,clc
A = readmatrix('875nm.txt'); % faster
x = A(:,1);
y = A(:,2);
[~,imax] = max(y);
% Total area
area_tot = trapz(x,y)
%area_tot = -4.5442e+03
% Area below peak
window = 200; % must be wider than expected peak
threshold_above_curve = 0.25; % above 0 and less than 0.5
[val,ind] = max(y);
x_tmp = x(ind-window/2:ind+window/2);
y_tmp = y(ind-window/2:ind+window/2);
y_tmp_d = detrend(y_tmp);
y_tmp_d = y_tmp_d - min(y_tmp_d);
ind = find(y_tmp_d>threshold_above_curve);
area_peak = trapz(x_tmp(ind),y_tmp(ind))
figure
plot(x,y,x_tmp(ind),y_tmp(ind),'r');
  4 Comments
Sam Chak
Sam Chak on 11 Apr 2022
Another +1
Mathieu NOE
Mathieu NOE on 11 Apr 2022
thanks again !
it's the beginning of the glory ! haha

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Davide Masiello
Davide Masiello on 11 Apr 2022
Edited: Davide Masiello on 11 Apr 2022
clear,clc
A = readtable('875nm.txt');
x = A.Var1;
y = A.Var2;
[~,imax] = max(y);
% Total area
area_tot = trapz(x,y)
area_tot = -4.5442e+03
% Area below peak
area_peak = trapz(x(imax-50:imax+50),y(imax-50:imax+50))
area_peak = -26.6612
figure
plot(x,y,x(imax-50:imax+50),y(imax-50:imax+50),'r')
Mind that the areas are both negative because your curve is almost all below the x axis.
  2 Comments
Haris Ashraf
Haris Ashraf on 11 Apr 2022
Here you assumed that peak will start and end 50 points ahead and back from the index of the peaks respectviely. Is there any particular reason for this assumption?
Davide Masiello
Davide Masiello on 11 Apr 2022
Edited: Davide Masiello on 11 Apr 2022
No, you can vary that number depending on what you decide your peak is. I have added a plot in my answer to show you what 50 points around the maximum actually encompasses.

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