Extract Value from ODE45
4 views (last 30 days)
Show older comments
I am Using below code to plot 2 graphs using ODE45. However I want to know a particular value of "t" at y(2) = 0.1
Is it possible?
%For plots
[t,y] = ode45(@odefun3,[0:0.1:50],[300; 2]);
plot(t,y(:,1))
plot(t,y(:,2))
function dydt = odefun3(t,y)
dydt = zeros(2,1);
dydt(1) = 125*0.01725*exp(-2660*(1/y(1)-1/300))*y(2)^2;
dydt(2) = -0.01725*exp(-2660*(1/y(1)-1/300))*y(2)^2;
end
0 Comments
Answers (1)
Walter Roberson
on 16 Mar 2022
No, you can only interpolate the position, as there is no t value at which y(:,2) is exactly 0.1.
%For plots
[t,y] = ode45(@odefun3,[0:0.1:50],[300; 2]);
plot(t,y(:,1))
plot(t,y(:,2))
format long g
t01 = interp1(y(:,2), t, 0.1, 'spline')
function dydt = odefun3(t,y)
dydt = zeros(2,1);
dydt(1) = 125*0.01725*exp(-2660*(1/y(1)-1/300))*y(2)^2;
dydt(2) = -0.01725*exp(-2660*(1/y(1)-1/300))*y(2)^2;
end
See Also
Categories
Find more on Ordinary Differential Equations in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!