How to resolve the problem in for loop?

3 views (last 30 days)
Ammy on 27 Feb 2022
Commented: Ammy on 27 Feb 2022
import java.math.*;
A = BigInteger('12345678934');
B = BigInteger('10');
for i =1:double(10)
i = BigInteger('i');
X(i) = i.multiply(A);
end
I'm facing the following error
Java exception occurred:
java.lang.NumberFormatException: For input string: "i"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:580)
at java.math.BigInteger.<init>(BigInteger.java:470)
at java.math.BigInteger.<init>(BigInteger.java:606)
How to resolve this issue?
Thanking in anticipation.

Walter Roberson on 27 Feb 2022
import java.math.*;
A = BigInteger('12345678934');
B = BigInteger('10');
for i =1:double(10)
iB = BigInteger(i);
X(i) = iB.multiply(A);
end
X(1), X(2), X(end)
ans = 12345678934 ans = 24691357868 ans = 123456789340
Walter Roberson on 27 Feb 2022
If i can reach more than 2^53 then you would need a slightly different approach.
Ammy on 27 Feb 2022
Thank you very much!