Unrecognized function or variable
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Hello!
I am trying to perform a linear interpolation within a vector of 100 points (beta) so that I can use it in the integrations. When I try to do that matlab gives me the following error: Unrecognized function or variable 'index'.
I do this as part of an optimization program using fmincon where Ti Tf and beta are the optimized variables
I have attached my code below (t is the integration time given by ODE45). Thanks to anyone who can help me!
function [B] = interp(t)
global beta Ti Tf
p = 100;
b1 = beta;
tspan = linspace(Ti,Tf,p);
dt = (Tf-Ti)/(p-1);
for i = 1:length(tspan)
if (t>=tspan(i) && t<tspan(i)+dt)
index=i;
end
end
if index<=(p-2)
if t>=tspan(index)
B = b1(index)+(b1(index+1)-b1(index))*(t-tspan(index))/dt;
else
B = b1(index);
end
else
B = b1(index);
end
end
Answers (1)
Walter Roberson
on 6 Jan 2022
Edited: Walter Roberson
on 6 Jan 2022
for i = 1:length(tspan)
if (t>=tspan(i) && t<tspan(i)+dt)
index=i;
end
end
That only sets index in the case that the if matched something . If it does not, then you never assign to index .
In particular, if t < Ti or t >= Tf or if Ti then you do not assign to index.
Questions:
- why do you keep searching once you do find a match?
- what if t is non-scalar ?
- why are you not using interp1() ?
6 Comments
Walter Roberson
on 6 Jan 2022
Piecewise linear interpolation is not compatible with any of the ode*() functions. The mathematics of the ode*() functions require that the functions are twice differentiable in order to get accurate answers. Piecewise linear interpolation does not have a continuous first derivative.
If you have a data table and you need interpolation, then 'spline' satisfies first and second derivative continuity... but of course spline can "ring" near sharp boundaries.
In any case... what would it hurt to add a test for t < tspan(1) or t >= tspan(end) . Maybe an
assert(t >= tspan(1) & t < tspan(end), 'time out of range')
Mal
on 7 Jan 2022
John D'Errico
on 7 Jan 2022
Edited: John D'Errico
on 7 Jan 2022
You never did answer why it is you are not using interp1. Never write your own code to do poorly what already exists in the form of well written code by a professional at the art.
Mal
on 7 Jan 2022
Walter Roberson
on 7 Jan 2022
That interp1() call is doing linear interpolation. As I already explained, linear interpolation is not compatible with mathematics of ode*() .
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