please have a look into matlab code once.

I have attached the image of plot which is need to be obtained

Thank you

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I am not able to generate the curve of FIg.5 as per attached pdf or given link below

I am trying to replicate the same but having some problem. Please solve the same

Thank you

clear all

clc

for i=1:2

alpha(i)= (pi*22)/180;

beta(i)= atan(cos(alpha(i))*sin(gamma(i))./(1+sin(alpha(i))*sin(gamma(i))));

end

R=0.4;

t(1)= R*cos(alpha(1))./cot(alpha(1)+beta(1));

t(2)= R*cos(alpha(2))./cot(alpha(2)+beta(2));

n_1=1.49;

theta_1= asin(n_1.*sin(alpha(1)))-alpha(1);

T=0.2;

H_1=0.1;

t(3)= (H_1-t(1)*(tan(alpha(1))-cot(theta_1)))./(cot(theta_1)-tan(alpha(2)));

t(4)= (t(2)*(tan(alpha(2))-cot(theta_1))+.....

T*(tan(alpha(1))-tan(alpha(2)))-H_1)./(tan(alpha(1))-cot(theta_1));

h_1=(T-t(1)-t(4))*tan(alpha(1));

h_2=(T-t(3)-t(2))*tan(alpha(2));

n_2=1.49;

lamda_min=0.004;

lamda_max=0.007;

phase= h_1*(n_1 -1)./(lamda_min)+ h_2*(n_2-1)./(lamda_min);

e1= (sin(pi*((1-(phase/2*pi))))/(pi*((1-(phase/2*pi)))))^2;

e2= (sin(pi*(t(1)/T))/(pi*(t(1)/T)))^2;

e3= (sin(pi*(t(2)/T))/(pi*(t(2)/T)))^2;

e4= (sin(pi*(t(3)/T))/(pi*(t(3)/T)))^2;

e5= (sin(pi*(t(4)/T))/(pi*(t(4)/T)))^2;

x=0.001;

f=0.025;

syms x

b= int(R-sqrt(R.^2-x.^2),0, f);

c=sqrt((1/f)*b);

e6= exp(((-4*pi*c)/lamda_min).^8);

effic= e1*e2*e3*e4*e5*e6;

syms lamda

pide=int(e1*e2*e3*e4*e5, lamda_min,lamda_max);

fpide= (1/(lamda_max-lamda_min))*pide;

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