Why does inequality give different values even though its evaluating the exact same matrix ??
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HabenG
on 11 Dec 2021
Commented: Walter Roberson
on 11 Dec 2021
Howcome these two yield different values ??
load td
version1 = sort(td(td(:,5) < 11.29))
t = (td(:,5));
version2 = sort(t(t < 11.29))
version1 - version2
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Accepted Answer
Walter Roberson
on 11 Dec 2021
sort(td(td(:,5) < 11.29))
td is a 2D array with multiple columns. You construct a mask from one of the columns, and you use it to index the entire td array -- which by linear indexing is going to effectively have it operate on the first column.
t = (td(:,5));
sort(t(t < 11.29))
but here you extract the column and your linear indexing is against the extracted version that only contains the one column.
2 Comments
Walter Roberson
on 11 Dec 2021
version3 = sort(td(td(:,5) < 11.29, 5))
is a possible way. But your second version with a temporary variable works well and is easier to read.
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