Input a variable into a plot title

I've trawled through these forums and found loads on inputting variables as titles, however, none of them work for me. Im trying to change the title of a plot with respect to a parameter the user will enter in the function. First i call a string for example

str = sprintf('just an example of %d that isnt working', variable)
title(str)

However only the 'just an example of' is printed out on the title of the plot, everything after and including the variable has dissapeared, this happens when i move the variable about in the title too.

Cheers!

[Star Strider]

Your code works perfectly for me (R2014a) with the string you posted. I can’t reproduce the error you report.

[Soumitra Vadnerkar]

How about this, given in help documentation:

figure

plot((1:10).^2)

f = 70;

c = (f-32)/1.8;

title(['Temperature is ',num2str(c),' C'])

[Alan Keenan]

The answer given by Soumitra Vadnerkar works well for me.

Answer 1

[Steven Lord]

With the introduction of the string array in release R2016b (and the ability to enclose text data in double quotes to create a string in release R2017a) you can also use:

plot((1:10).^2)
f = 70;
c = (f-32)/1.8;
title("Temperature is " + c + " C")

[Giuseppe Degan Di Dieco]

Brilliant and easy, thanks!

Best.

Answer 2

[Adam]

title( ['just an example of ' num2str( variable ) ' that isnt working'] )

Does that work?

[Peter]

If i try to make that for two variable they appear together

Some idea to solve that?

[Adam]

Two variables in what way?

You can concatenate as many substrings as you want in this way so you don't have to include all variables in the one middle part, you can add an e.g.

', '

between two variables.

[Peter]

Okey, i had a syntaxis problem with that. Sorry.

[Adam]

title( ['just an example of ' num2str( variable ) ', ' num2str( otherVariable ) ' that isnt working'] )

[Image Analyst]

Peter, then use the sprintf() version. In my opinion, I think it's easier and more straightforward than using num2str and all those quotes.

[Walter Roberson]

Dayan Guerra comments to Adam

Thank you, this is the only way I can it work, the sprintf() version is not working at all on mt2013

[Walter Roberson]

sprintf() would work fine in R2013* . However, the example given

str = sprintf('just an example of %d that isnt working', variable)

would be best for the case where the variable is an integer. If you have a variable that is numeric but not an integer, you would use a %e or %f or %g format.

[Adam]

sprintf is definitely a neater approach. Back in 2014 I was less familiar with using sprintf so it didn't spring to mind for this!

Answer 3

[MathWorks Support Team]

How about this, given in help documentation:

plot((1:10).^2)
f = 70;
c = (f-32)/1.8;
title(['Temperature is ',num2str(c),' C'])

[MathWorks Support Team]

Thanks Soumitra Vadnerkar for this answer.

[Giuseppe Degan Di Dieco]

Thank you for highlighting the documentation's content to beginners!

Best.