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If same value apperas in array count +1

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First Last
First Last on 14 Sep 2021
Commented: First Last on 14 Sep 2021
Hello Guys,
I have an array with nx1, now i need a code to count + 1 if the same value apperas later in the array, for example:
input = [ 1 2 3 4 1 2 3 4 1 2 3 4 ];
output = [ 1 1 1 1 2 2 2 2 3 3 3 3];
Thank you

Accepted Answer

Walter Roberson
Walter Roberson on 14 Sep 2021
input = [ 1 2 3 4 1 2 3 4 1 2 3 4 ];
output = sum(triu(input' == input))
output = 1×12
1 1 1 1 2 2 2 2 3 3 3 3
  1 Comment
First Last
First Last on 14 Sep 2021
Thats it, thank you Walter :) you saved my day

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More Answers (1)

KSSV
KSSV on 14 Sep 2021
input = [ 1 2 3 4 1 2 3 4 1 2 3 4 ];
a = reshape(input,[],3)' ;
[c,ia,ib] = unique(a,'rows') ;
ib
  1 Comment
First Last
First Last on 14 Sep 2021
Thank you KSSV,
but i the output is a little bit diffrent

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