Decrementing step for loop I matlab

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Dennis M
Dennis M on 24 Aug 2021
Commented: Dennis M on 24 Aug 2021
y = zeros(1,12);
for i = 1:12
y(i+1) = y(i) + ((5 - (4/50)*y(i)));
end
y
x = zeros(1,10);
for i = 10:-1:2
x(i-1) = x(i) + ((5 + (4/50)*x(i)));
end
x
Good Day,
May I ask how can I insert the start and stop variable on above code? for example I want to start in 17 to 30 or 15 to 2 with decrementing step.
Thanks and Regards,
Dennis

Answers (1)

Awais Saeed
Awais Saeed on 24 Aug 2021
Edited: Awais Saeed on 24 Aug 2021
% start, step, and end points
starty = 1;
endy = 12;
startx = 10;
endx = 2;
decrement = -1;
y = zeros(1,12);
for i = starty:endy
y(i+1) = y(i) + ((5 - (4/50)*y(i)));
end
y
x = zeros(1,10);
for i = startx:decrement:endx
x(i-1) = x(i) + ((5 + (4/50)*x(i)));
end
x
  3 Comments
Dennis M
Dennis M on 24 Aug 2021

<<

>> There was error when I change the variables, I have to change also the y = zeros(1,12); defend on the length. I want a loop that the output is like this (10 20 29 38 47 56 65 and so on) and (80 70 61 53 46 40 35 and so on) same in negative (-10 -20 -29 -38 -47 -56 -65 and so on) and (-80 -70 -61 -53 -46 -40 -35 and so on)

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