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matlabpool open n; doesn't work.

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Martin on 7 May 2014
Commented: Bruno Silva on 17 Jan 2020
I'd like to open matlabpool with a variable number of cores, to use the maximum number of cores available. So n would equal features('numCores') here.
But matlabpool open n, matlabpool open features('numCores'), matlabpool open maxNumCompThreads don't work here. matlabpool open seems to accept only numbers and not variables.
I could do something stupid like
if features('numCores') == 4
matlabpool open 4;
elseif features('numCores') == 2
matlabpool open 2;
but I'd like to know if something more elegant exists.

Accepted Answer

Niklas Nylén
Niklas Nylén on 7 May 2014
Edited: Niklas Nylén on 7 May 2014
This is because writing arguments like this:
matlabpool open 2
is the same as passing the strings 'open' and '2' to the matlabpool function, i.e. the equivalent to
What you can do is to call matlabpool like this:
matlabpool('open', num2str(features('numCores')))
Possibly you can also pass the number of cores directly, but since I do not have parallell computing toolbox I can't test it, like so:
matlabpool('open', features('numCores'))

More Answers (2)

Matt J
Matt J on 7 May 2014
Edited: Matt J on 7 May 2014
If you have R2013b or later, you shouldn't be using matlabpool . You should be using parpool , which does take a variable as input directly,
Haseeb Hassan
Haseeb Hassan on 7 Oct 2018
Thank you Matt for your useful hint.

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Malshikho on 25 May 2018
Unfortunately I have Matlab R2010b
  1 Comment
Steven Lord
Steven Lord on 25 May 2018
Then use matlabpool using the syntax described in the accepted answer by Niklas Nylén.

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