Akshay Gore
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Feeds
Submitted
CoCMA: Energy-Efficient Coverage Control in Cluster-Based Wi
CoCMA: Energy-Efficient Coverage Control in Cluster-Based Wireless Sensor Networks Using a Memetic Algorithm
5 years ago | 128 downloads |
Submitted
Digital Mammography Image Enhancement Using Improved
% Code Work Team % To report your comment or any bug please send e-mail to: %
5 years ago | 2046 downloads |
Submitted
Canny Edge Detection Enhancement by Scale Multiplication
Canny Edge Detection Enhancement by Scale Multiplication
5 years ago | 1265 downloads |
Submitted
Developed Distributed Energy-Efficient Clustering (DDEEC)
Contact for code akshaygore@live.com #WSN #matlab %#leach # image processing
5 years ago | 599 downloads |
Submitted
E-DEEC- Enhanced Distributed Energy Efficient Clustering
Contact for code akshaygore@live.com #WSN #matlab %#leach # image processing
6 years ago | 979 downloads |
Submitted
Energy Efficient Sleep Awake Aware (EESAA)
Contact for code akshaygore@live.com #WSN #matlab %#leach # image processing
6 years ago | 1400 downloads |
Submitted
Orthogonal Laplacianfaces for Face Recognition
Contact for code Code Work Team https://www.codewrk.com/ admin@codewrk.com #WSN #matlab %#leach # image processing
7 years ago | 516 downloads |
Submitted
Image Quality Assessment Based on InterPatch and Intra-Patch
Contact for code Code Work Team https://www.codewrk.com/ admin@codewrk.com #WSN #matlab %#leach # image processing
7 years ago | 455 downloads |
Question
How to calculate gradient of 512*512*4 image?
Is this wrong or write? If my output image is g(512*512*4) then gradient of g() is gradver1=sqrt(g1(:,:,1).^2+g1(:,:,2).^...
12 years ago | 1 answer | 0
1
answerQuestion
How to calculate pixel with same gray value are labeled with same number,for each kernal in the image?
How to calculate pixel with same gray value are labeled with same number,for each kernal in the image?
13 years ago | 1 answer | 0
1
answerQuestion
how contours are approximated by rectangles.
output required is shown in image.
13 years ago | 0 answers | 0
